PHP newb needs help with syntax please

[bgbs]

I need to rewrite this php statement

<img src="<?php bloginfo('template_directory'); ?>/images/mainimage.jpg" title="" alt="" />

 

When I try to do this

<?php echo '<img src="<?php bloginfo('template_directory'); ?>/images/mainimage.jpg" title="" alt="" />' ; ?>

It does not work, because I guess I've open and closed a php code inside php.

 

How do I properly write this statement?

 

Thanks

Ben

[dzelenika]

What is html source of this code

[bgbs]

This is used by wordpress, but I know Im not properly wrapping it in echo statement

[dzelenika]

what about this?

 

<?php 
echo '<img src="';
bloginfo('template_directory'); 
?>/images/mainimage.jpg" title="" alt="" />'

[herghost]

Your are already writing in php so why are you opening another php block? try removing the <?php & ?> in the middle of your code!

[bgbs]

  Quote

Your are already writing in php so why are you opening another php block? try removing the <?php & ?> in the middle of your code!

 

You mean like this?

 <?php  echo '<img src="bloginfo('template_directory')/images/image.png" title="" alt="" />'; ?>

 

This doesnt work

[bgbs]

  Quote

what about this?

 

<?php 
echo '<img src="';
bloginfo('template_directory'); 
?>/images/mainimage.jpg" title="" alt="" />'

 

This will not work, because the whole echo statement needs to be wrapped in php tags. I just tried this and it is working half way

echo '<img src="'. bloginfo('template_directory') .'/images/image.png" title="" alt="" />';

 

But it outputs, when viewing html source, as:

http://site.com/wp-content/themes/mytheme <img alt="" title="" src="/images/image.png">

[dzelenika]

Could you post entire php file or at least while function or class please?

 

[bgbs]

  Quote

Could you post entire php file or at least while function or class please?

 

 

It is a huge php file with pages of code wrapped in php tags.  And in between those tags, I'm just trying to add a statement to output an image from images folder, and instead of echoing full url path, I'm using the wordpresses path to template folder, and how to do this properly in echo is where I'm stock right now.

But as I posted above here is what I've been able to do

echo '<img src="'. bloginfo('template_directory') .'/images/image.png" title="" alt="" />';

 

But it outputs, when viewing html source, as:

http://site.com/wp-content/themes/mytheme <img alt="" title="" src="/images/image.png">

[dzelenika]

  Quote

  Quote

Could you post entire php file or at least while function or class please?

 

 

It is a huge php file with pages of code wrapped in php tags.  And in between those tags, I'm just trying to add a statement to output an image from images folder, and instead of echoing full url path, I'm using the wordpresses path to template folder, and how to do this properly in echo is where I'm stock right now.

But as I posted above here is what I've been able to do

echo '<img src="'. bloginfo('template_directory') .'/images/image.png" title="" alt="" />';

 

But it outputs, when viewing html source, as:

http://site.com/wp-content/themes/mytheme <img alt="" title="" src="/images/image.png">

 

As I understand you this is what you need:

 

echo '<img src="';
bloginfo('template_directory');
echo '/images/image.png" title="" alt="" />';

[bgbs]

That worked!

But wait, why did you have to break this to two separate echo statements?  Why couldn't this be wrapped all in one echo?

 

Thanks for your help

Ben

[dzelenika]

function

 

bloginfo('template_directory')

 

doesn't return but echoes value so there's no need to include it in echo!

[bgbs]

  Quote

function

 

bloginfo('template_directory')

 

doesn't return but echoes value so there's no need to include it in echo!

 

I see

I appreciate your help.