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Is the name of the page we're working on called checklogin2.php?

 

yes it goes from loginre1.php to checklogin2.php and from there it should go to login_success.php, login_success2.php or login_success4.php (depending on user year)

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Change to this

<?php
session_start(); 
//ini_set('session.bug_compat_42',0);
//ini_set('session.bug_compat_warn',0);
$host="localhost"; // Host name
$username="phpuser"; // username
$password="phpuser"; // password
$db_name="phpsite"; // Database name
$tbl_name="users"; // Table name

// Replace database connect functions depending on database you are using.
mysql_connect("$host", "$username", "$password");
mysql_select_db("$db_name");

//Add isset 
if (isset($_POST['UsersID'])){
//submitting query
// username and password sent from form
//NEVER Remove the mysql_real_escape_string. Else there could be an Sql-Injection!
$UsersID=mysql_real_escape_string($_POST['UsersID']);
$U_Password=mysql_real_escape_string($_POST['U_Password']);

$sql="SELECT UsersID,U_YearID FROM users WHERE UsersID='$UsersID' and U_Password='$U_Password'";
//echo $sql; 
$result = mysql_query($sql);
$result2=mysql_fetch_row($result);

//checking results
// Replace counting function based on database you are using.
$count=mysql_num_rows($result);
// If result matched $myusername and $mypassword, table row must be 1 row

//Direct Userbased on result
if($count==1){
  // Register $UsersID, $U_Password and redirect to file "login_success.php"
/*
  $_SESSION['UsersID']=$result[0];
  $_SESSION['U_YearID']=$result[1];
  if($_SESSION['U_YearID']==1){  
  header("location:login_success.php");
exit;
}
  if($_SESSION['U_YearID']==2){
  header("location:login_success2.php");
exit;
}
  if($_SESSION['U_YearID']==4){
  header("location:login_success4.php");
exit;
}
*/ 
echo "{$result2[1]}"; 
} else {

  echo "Wrong Username or Password";
}
}
?>

Change to this line

$result=mysql_fetch_row($sql);

 

i get this

Warning: mysql_fetch_row() expects parameter 1 to be resource, string given in C:\xampp\htdocs\Site1\test\checklogin2.php on line 29

 

Warning: mysql_num_rows() expects parameter 1 to be resource, null given in C:\xampp\htdocs\Site1\test\checklogin2.php on line 32

Wrong Username or Password

Now try this

<?php
session_start(); 
//ini_set('session.bug_compat_42',0);
//ini_set('session.bug_compat_warn',0);
$host="localhost"; // Host name
$username="phpuser"; // username
$password="phpuser"; // password
$db_name="phpsite"; // Database name
$tbl_name="users"; // Table name

// Replace database connect functions depending on database you are using.
mysql_connect("$host", "$username", "$password");
mysql_select_db("$db_name");

//Add isset 
if (isset($_POST['UsersID'])){
//submitting query
// username and password sent from form
//NEVER Remove the mysql_real_escape_string. Else there could be an Sql-Injection!
$UsersID=mysql_real_escape_string($_POST['UsersID']);
$U_Password=mysql_real_escape_string($_POST['U_Password']);

$sql="SELECT UsersID,U_YearID FROM users WHERE UsersID='$UsersID' and U_Password='$U_Password'";
$result = mysql_query($sql);
$result2=mysql_fetch_row($result);

//checking results
// Replace counting function based on database you are using.
$count=mysql_num_rows($result);
// If result matched $myusername and $mypassword, table row must be 1 row

//Direct Userbased on result
if($count==1){
  // Register $UsersID, $U_Password and redirect to file "login_success.php"

  $_SESSION['UsersID']=$result2[0];
  $_SESSION['U_YearID']=$result2[1];
  if($_SESSION['U_YearID']==1){  
  header("location:login_success.php");
exit;
}
  if($_SESSION['U_YearID']==2){
  header("location:login_success2.php");
exit;
}
  if($_SESSION['U_YearID']==4){
  header("location:login_success4.php");
exit;
}
} else {

  echo "Wrong Username or Password";
}
}
?>

Now try this

<?php
session_start(); 
//ini_set('session.bug_compat_42',0);
//ini_set('session.bug_compat_warn',0);
$host="localhost"; // Host name
$username="phpuser"; // username
$password="phpuser"; // password
$db_name="phpsite"; // Database name
$tbl_name="users"; // Table name

// Replace database connect functions depending on database you are using.
mysql_connect("$host", "$username", "$password");
mysql_select_db("$db_name");

//Add isset 
if (isset($_POST['UsersID'])){
//submitting query
// username and password sent from form
//NEVER Remove the mysql_real_escape_string. Else there could be an Sql-Injection!
$UsersID=mysql_real_escape_string($_POST['UsersID']);
$U_Password=mysql_real_escape_string($_POST['U_Password']);

$sql="SELECT UsersID,U_YearID FROM users WHERE UsersID='$UsersID' and U_Password='$U_Password'";
$result = mysql_query($sql);
$result2=mysql_fetch_row($result);

//checking results
// Replace counting function based on database you are using.
$count=mysql_num_rows($result);
// If result matched $myusername and $mypassword, table row must be 1 row

//Direct Userbased on result
if($count==1){
  // Register $UsersID, $U_Password and redirect to file "login_success.php"

  $_SESSION['UsersID']=$result2[0];
  $_SESSION['U_YearID']=$result2[1];
  if($_SESSION['U_YearID']==1){  
  header("location:login_success.php");
exit;
}
  if($_SESSION['U_YearID']==2){
  header("location:login_success2.php");
exit;
}
  if($_SESSION['U_YearID']==4){
  header("location:login_success4.php");
exit;
}
} else {

  echo "Wrong Username or Password";
}
}
?>

 

YES!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!  :D

 

You my sir are a genius :) Thank you soooo much i can finally click solved!! :)

Now look into encoding your passwords.  At the very least use MD5 on both your log in scripts and creating account scripts.

$U_Password=MD5($U_Password);

 

ok i will look into that tomorrow as its 1am in the UK right now and i have been at this all day! lol thanks again!!!

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