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I was wondering if someone can tell me what I have done wrong with this code:

 

<?php
    foreach ($row['received'] as $data) {
        $data += $received;
    }
    echo $received;
?>

It should be adding the number 2 three times, so it should be echoing 6 but its not.

 

Problem 1 I have is that nothing is being added to the variable $received, and problem 2 is that I suspect $received will not become 6, but rather 222. Am I correct?

i dont quite see how the value of $received is being assigned?

 

You are adding it's value to$data and then echoing out $received - but why would that display your new value?

 

try this to test it

 

foreach($row['received'] as &$data) {

$data += $received;
echo $data;
echo "<br/>";
}


print_r($row['received']);

 

Also you need to pass data by reference or it wont change outside of the loop.

You are using the same object for the loop iteration as you are the counter so your $data object is reset each time during the loop.

Use a different object for your counter and you should be fine, and make sure you initialize it to zero.

I did this:

 

<?php
$received = 0;
while ($row = mysql_fetch_assoc($result)) {
	foreach ($row as $data) {
		$received = $data['received'] + $received;
	}
}
echo $received;
?>

 

I now have two rows of "received", which are '15' and '1'. So, with the above code I was expecting to get 16... but guess what I got?! 7!... I don't know why this happened!

It didn't work, but this did:

 

<?php
$received = 0;
$query = "SELECT * FROM finances";
$result = mysql_query($query);
while ($row = mysql_fetch_assoc($result)) {
	$received = $row['received'] + $received;
}
echo "Received: $".$received." AUD";
?>

 

Much thanks to you, I solved it.

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