FastbackJon Posted February 10, 2012 Share Posted February 10, 2012 I have found that when I go to a page on my website, it can cause my IP to get blocked for 1/2 hour by their servers. I have confirmed this by using a proxy to see the site is still up and running. I contacted tech support for the server and after hours and hours of not being able to identify the issue, their tech support accused me of writing bad PHP code. The code has not changed, and this has been a recent issue with the server (last few months). The web page queries a SQL database and displays many small thumbnails. So I took the code from that page, trimmed it down to just get the contents of the image directory and display the thumbnails. Very basic, whereas before it queried the database for specific images, and created thumbnails on the fly. And so the very basic page (link below) without all that extra stuff STILL causes my IP to be blocked from the site when I access the page. http://www.1966-67chargerregistry.com/gallery/indexTest.php Can you guys confirm that it's not a coding issue? Sure I could split up the images onto multiple pages, but there should be nothing here that a decent server can't handle, right? All thumbnails are 2-3 kb and there's typically maybe 1000 of them. Thanks!!! Re-factored PHP code below: <html> <head><title></title></head> <body> <table align="center" width="1000"> <?php //get contents of image directory so we can look for existing images later in loop $filePath = '../66pics/seppics'; $imageFiles = scandir($filePath); $output = ''; $added = 0; //walk through each of the directory image results for($i = 0; $i < count($imageFiles); $i++) { //only display thumbnail images if(substr($imageFiles[$i], 0, 1) == 'T' && strlen($imageFiles[$i]) > 10) { //save each image in a table cell to write out later $output .= chr(13).'<td><center><img src="'.$filePath.'/'.$imageFiles[$i].'"></center></td>'; $added++; //write out 7 pictures on each table row if($added%7 == 0) { echo chr(13).'<tr>'.$output.chr(13).'</tr>'; $output = ''; } } } //end for loop //output final incomplete line if(strlen($output) > 0) { echo chr(13).'<tr>'.$output.chr(13).'</tr>'; } ?> </table></body></html> Quote Link to comment Share on other sites More sharing options...
FastbackJon Posted February 10, 2012 Author Share Posted February 10, 2012 Well I decided to "View Source" on the php output since it's just outputting HTML. I can save the source showing all the images and the rows in an .html file, then upload that, and access that to see if the problem keeps happening. That way I can rule out PHP and "critically bad coding" as one tech support admin put it, all together. Web Hosting Pad is terrible. Quote Link to comment Share on other sites More sharing options...
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