zocker Posted February 24, 2012 Share Posted February 24, 2012 Greetings and thanks in advance! I got this script from http://www.phpeasystep.com/mysql/9.html for which I give much thanks. It takes user input and uses it to UPDATE a mysql db, the actual row concerned being chosen by a previous script. The script runs purrfectly unless I add another db field to be updated. After what seems like several years I narrowed it down to the form1 as coded below. This table posts only 3 fields to the script , if for exampleI change the order of the columns, only the first three are enntered into the $_REQUEST array on the next script...I think its something to do with the table layout??? so that in this example, $email = $_REQUEST['email'] (in the next script) throws an error. What is the problem please? And another question....this script has // close connection mysql_close(); I read that this is VERY bad practice.....your thoughts are welcomed. [pre]CODE ############### Code <?php $host="localhost"; // Host name $username="root"; // Mysql username $password=""; // Mysql password $db_name="soltheatre"; // Database name $tbl_name="members"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); // get value of id that sent from address bar $id=$_GET['id_user']; // Retrieve data from database $sql="SELECT * FROM $tbl_name WHERE id_user='$id'"; $result=mysql_query($sql); $rows=mysql_fetch_array($result); ?> <table width="400" border="0" cellspacing="1" cellpadding="0"> <tr> <form name="form1" method="post" action="update_ac.php"> <td> <table width="100%" border="0" cellspacing="1" cellpadding="0"> <tr> <td> </td> <td colspan="4"><strong>Update data in mysql</strong> </td> </tr> // ******** somewhere here there are not enough fields or columns defined. ************** <tr> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> <td align="center"> </td> </tr> <tr> <td align="center"> </td> <td align="center"><strong>Name</strong></td> <td align="center"><strong>Username</strong></td> <td align="center"><strong>phonenumber</strong></td> <td align="center"><strong>E-mail</strong></td> </tr> <tr> <td> </td> <td align="center"><input name="name" type="text" id="name" value="<? echo $rows['name']; ?>"></td> <td align="center"><input name="username" type="text" id="username" value="<? echo $rows['username']; ?>" size="15"></td> <td align="center"><input name="phonenumber" type="text" id="phonenumber" value="<? echo $rows['phonenumber']; ?>" size="15"></td> <td align="center"><input name="phonenumber" type="text" id="email" value="<? echo $rows['email']; ?>" size="15"></td> </tr> <tr> <td> </td> <td><input name="id" type="hidden" id="id" value="<? echo $rows['id_user']; ?>"></td> <td align="center"><input type="submit" name="Submit" value="Submit"></td> <td> </td> </tr> </table> </td> </form> </tr> </table> <? // close connection mysql_close(); ?>[/pre] Quote Link to comment https://forums.phpfreaks.com/topic/257684-variable-not-being-passed/ Share on other sites More sharing options...
givememore Posted February 24, 2012 Share Posted February 24, 2012 the name of the input field is wrong in the email input. <td align="center"><input name="phonenumber" type="text" id="email" value="<? echo $rows['email']; ?>" size="15"></td> The name "phonenumber" is already used in the field above. Try to call it '... name="email" ...'. Quote Link to comment https://forums.phpfreaks.com/topic/257684-variable-not-being-passed/#findComment-1320724 Share on other sites More sharing options...
zocker Posted February 24, 2012 Author Share Posted February 24, 2012 Thanks! Z Quote Link to comment https://forums.phpfreaks.com/topic/257684-variable-not-being-passed/#findComment-1320881 Share on other sites More sharing options...
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