stan003 Posted February 26, 2012 Share Posted February 26, 2012 HI, I have some code that obtains the ip address of the visitor and then looks up their ip address, a copy of the code is below: function getRealIpAddr() { if (!empty($_SERVER['HTTP_CLIENT_IP'])) //check ip from share internet { $ip=$_SERVER['HTTP_CLIENT_IP']; } elseif (!empty($_SERVER['HTTP_X_FORWARDED_FOR'])) //to check ip is pass from proxy { $ip=$_SERVER['HTTP_X_FORWARDED_FOR']; } else { $ip=$_SERVER['REMOTE_ADDR']; } return $ip; } function IPtoLatLng($ip) { $latlngValue=array(); $dom = new DOMDocument(); $ipcheck = ip2long($ip); if($ipcheck == -1 || $ipcheck === false){ echo "ERROR: INVALID IP"; exit; } else $uri = "http://api.hostip.info/?ip=$ip&position=true"; No what i want to do is swap the GetRealIp for a php variable, however when i write the code like this: $ip = "$ip"; function IPtoLatLng($ip) { $latlngValue=array(); $dom = new DOMDocument(); $ipcheck = ip2long($ip); if($ipcheck == -1 || $ipcheck === false){ echo "ERROR: INVALID IP"; exit; } else $uri = "http://api.hostip.info/?ip=$ip&position=true"; $dom->load($uri); $name=$dom->getElementsByTagNameNS('http://www.opengis.net/gml','name')->item(1)->nodeValue; $coordinates=$dom->getElementsByTagNameNS('http://www.opengis.net/gml','coordinates')->item(0)->nodeValue; $temp=explode(",",$coordinates); $latlngValue['LNG']=$temp[0]; $latlngValue['LAT']=$temp[1]; $latlngValue['NAME']=$name; return $latlngValue; } It returns Invalid IP, however no matter what i try i get the same response over and over again. Any suggestions would be appreciated. Thanks Stan Quote Link to comment https://forums.phpfreaks.com/topic/257792-swapping-ip-class-for-ip-variable/ Share on other sites More sharing options...
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