skwap Posted March 9, 2012 Share Posted March 9, 2012 Guys, i want to display ads after 4 items to be displayed. Iam fetching item using mysql database & iam showing 8 items per page. I used below code but its not working because i used the item id to specify the first number but the items is not listed as correct order <?php // first number $first = $row['id']; // second number $second = 4; //checking if the first number is muliple of second. If true then display ads. If($first % $second == "0") { echo 'ads to display'; } It will work if i list items in correct order. Please let me know correct solution. Thanks in advance ! Quote Link to comment https://forums.phpfreaks.com/topic/258565-display-ads-after-every-4-items/ Share on other sites More sharing options...
smerny Posted March 9, 2012 Share Posted March 9, 2012 something like this? $i = 0; for($row = mysql_fetch_assoc($result)){ If($i++ % 4 == "0") { echo 'ads to display'; } $row['whatever'] } Quote Link to comment https://forums.phpfreaks.com/topic/258565-display-ads-after-every-4-items/#findComment-1325423 Share on other sites More sharing options...
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