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Hi all ive got this code to display uploaded images from a database but at the moment it will only display one image.

Here is my code:

[code]
$gotten = @mysql_query("SELECT * FROM pix ORDER BY pid DESC");
if ($row = @mysql_fetch_assoc($gotten)) {
        $title = htmlspecialchars($row[title]);
        $bytes = $row[imgdata];
} else {
        $errmsg = "MySql Error!";
}


if ($_REQUEST[gim] == 1) {
        header("Content-type: image/jpeg");
        print $bytes;
        exit ();
        }
?>

<img src=?gim=1 width=80>[/code]

Now i know its controlled by the 'gim' variable but im not sure on how to modify this to made it display all the images contained in the database. Any help would be great! Thanks
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https://forums.phpfreaks.com/topic/25912-displaying-images-from-database/
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Pls try like this:
if ($_REQUEST[gim] == 1) {

$gotten = @mysql_query("SELECT * FROM pix ORDER BY pid DESC");
while($row = @mysql_fetch_array($gotten)) {
        $title = htmlspecialchars($row[title]);
        $bytes = $row[imgdata];
        header("Content-type: image/jpeg");
        print $bytes;
        } else {
        $errmsg = "MySql Error!";
}

}



Sorry if am wrong some where. Just felt like giviving a hint.
You can't do that... At least not in the way your thinking...

Example to show all images...

DisplayImage.php
[code]
<?php

$query = sprintf("SELECT * FROM `pix` WHERE `pid`='%d'", $_GET["gim"]); // mysql injection possible, quote $_GET["gim"] (research SQL injection)
$gotten = mysql_query($query) or die(mysql_error());
if($row = mysql_fetch_assoc($gotten))
{
$title = htmlspecialchars($row["title"]);
$bytes = $row["imgdata"];
}else{
        $errmsg = "MySql Error!";
}

header("Content-type: image/jpeg");
print $bytes;
exit();

?>
[/code]

Then, to show all the images...

ShowAll.php
[code]
<?php
$query = "SELECT * FROM `pix` ORDER BY `pid` DESC";
$gotten = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_assoc($gotten))
{
  echo '<img src="DisplayImage.php?gim=' . $row["pid"] . '" alt="' . htmlentities($row["title"]) . '">';
}
?>
[/code]

Hth, Note haven't tested or checked for errors :)

Thanks mate thats great! Ive got two error's. On displayimage.php it doesnt show an image just a broken image. Also in showall.php it says unexpected t_string on line 12 but ive tried putting bits here and there but it still comes up with the same error!  :-[ sorry to be a pain!
Thanks for the link but ive already achieved what the tutorial explains. I know how to upload an image and display it. The only trouble is i want to display all the images in the database which is achievable in the code heckenschutze gave me but i cant get it to work  :-\
Ok im getting somewhere now the code that heckenschutze has given me works apart from it wont show the images or the title. Although it does draw the title as an alt attribute. Someone please help i know im almost there with this!

here is the page: [url=http://www.alns.co.uk/ssrfc/showall.php]http://www.alns.co.uk/ssrfc/showall.php[/url]
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