dk4210 Posted March 19, 2012 Share Posted March 19, 2012 Hello Guys, I need some help converting this ajax call to jquery but I am clueless to how to do it.. Please advise Here is my code <script type="text/javascript"> function loadXMLDoc(imgID,isSold,order) { if(isSold == 1) $('.soldWatermark').css('display',''); else $('.soldWatermark').css('display','none'); var xmlhttp; if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("myDiv").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","artist_title.php?imgid=" + imgID ,true); xmlhttp.send(); } </script> The reason I want to change it to jquery is because I am seeing a strange error. When loading my site in IE - http://frameworksgallery.com/view_artist2.php?artist_id=Baskin_Fran 1. I click on the second thumbnail. 2. I click on the third thumb 3. I go back to the second thumb The large image does not display after re clicking. IE web developer tool says it is this that it's having an issue with xmlhttp=new XMLHttpRequest(); Thanks in advance.. Link to comment https://forums.phpfreaks.com/topic/259255-converting-ajax-to-jquery/ Share on other sites More sharing options...
AyKay47 Posted March 19, 2012 Share Posted March 19, 2012 $.ajax({ url: "artist_title.php", data: "imgid=" + imgID, success: function(data) { $("#myDiv").html(data); } }); Link to comment https://forums.phpfreaks.com/topic/259255-converting-ajax-to-jquery/#findComment-1329008 Share on other sites More sharing options...
dk4210 Posted March 19, 2012 Author Share Posted March 19, 2012 Thank you that worked! Link to comment https://forums.phpfreaks.com/topic/259255-converting-ajax-to-jquery/#findComment-1329022 Share on other sites More sharing options...
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