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transfer the values of a generated number using jquery without refreshing page

liomon41

By liomon41
in PHP Coding Help

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liomon41 Member

liomon41

Posted
Posted

<!DOCTYPE html>

<html>

<head>

 

<script>

 

$(document).ready(function() {

 

 

if($("#getPIN").click(function(){

 

<?php

$char = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890';

$generated_password = substr(str_shuffle($char), 0, 10);

?>

 

 

var genNumber;

 

$("#txtpin").val() = genNumber;

 

 

return false;

 

}));

 

 

   

});

 

</script>

</head>

 

 

<body>

 

<input type = "text" name = "txtpin" id = "txtpin" value = "">

<input type = "button" name = "getPIN" id = "getPIN" value = "getPIN">

 

</body>

 

</html>

 

 

Hey you guys need your help... Basically what im trying to do is when the user clicks the getPIN button, the value generated using php is assigned to the txtpin textfield without refreshing the page.... thanks alot guys....

seanlim Newbie

seanlim

Posted
Posted

Please make use of the code tags! This is more of a jQuery question anyway, since you've had all the PHP figured out.

 

You don't assign anything to the val() function; instead, pass the value to the function. i.e. $(obj).val('some value');

 

Also, you don't need the if conditional which serves no purpose and is probably syntactically wrong too.

 

<!DOCTYPE html>
<html>
<head>
<script type="text/javascript">

$(document).ready(function() {
   
   
   $("#getPIN").click(function(){
      
      <?php 
            $char = 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVW XYZ1234567890';
            $generated_password = substr(str_shuffle($char), 0, 10);
      ?>
      
      
      var genNumber = '<?php echo $generated_password; ?>';
      
      $("#txtpin").val(genNumber);
      
      
      return false;
      
   });
   
   
    
});

</script>
</head>


<body>

<input type = "text" name = "txtpin" id = "txtpin" value = "">
<input type = "button" name = "getPIN" id = "getPIN" value = "getPIN">

</body>

</html>

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