peehaichpee Posted March 21, 2012 Share Posted March 21, 2012 hey all so I have this bit down: $query="SELECT `2010 Region Code` AS codes FROM locations"; $results = mysql_query($query); $options=""; $options = "<select location='codes'>"; while($nt=mysql_fetch_assoc($results)) { $thing=$nt["codes"]; $options.="\r\n<option value ='{$nt['codes']}'> {$nt['codes']}</option>"; } $options .="\r\n</select>"; echo $options; what I'm trying to do is grab the selection from the drop down and display it as a table (the sql query would be extended should we manage to figure this one out I've tried echo"<form name='LOCATIONS' action='".$_SERVER['PHP_SELF']."' target='iframe' method='post'>"; any ideas? Quote Link to comment https://forums.phpfreaks.com/topic/259459-keep-a-variable-from-a-mysql-generated-drop-down/ Share on other sites More sharing options...
dragon_sa Posted March 21, 2012 Share Posted March 21, 2012 this is a javascript question, you dont need the form part $options.="<option value =\"page.php?code={$nt['codes']}" onchange=\"window.open(this.options[this.selectedIndex].value,'myIFrame')\">{$nt['codes']}</option>\r\n"; Give the iframe the name myIframe, create another page in this example called page.php and setup your table, the variable $_GET['code'] in this example will be available on the page.php page for you to build your table from Quote Link to comment https://forums.phpfreaks.com/topic/259459-keep-a-variable-from-a-mysql-generated-drop-down/#findComment-1330045 Share on other sites More sharing options...
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