mikemcg36 Posted March 23, 2012 Share Posted March 23, 2012 Hello, I have a drop down box that filters my table data by City and displays the results. It works! Now I am trying to add a second drop down menu to filter by name. When name is selected AND city is selected, the display should be the same names that live in the same city. Can anyone ties these 2 drop downs together for me? Here is my table: CREATE TABLE IF NOT EXISTS `data` ( `id` int(11) NOT NULL auto_increment, `from_date` date NOT NULL, `to_date` date NOT NULL, `full_name` varchar(250) NOT NULL, `email` varchar(250) NOT NULL, `city` varchar(250) NOT NULL, PRIMARY KEY (`id`) ) And here is the html and PHP in one file: <?php error_reporting(0); include("config.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>MySQL table search</title> <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.0/jquery.min.js"></script> <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.16/jquery-ui.min.js"></script> <link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/> <style> BODY, TD { font-family:Arial, Helvetica, sans-serif; font-size:12px; } </style> </head> <body> <form id="form1" name="form1" method="post" action="search.php"> <label>Name</label> <select name="name"> <option value="">--</option> <?php $sql = "SELECT * FROM ".$SETTINGS["data_table"]." GROUP BY full_name ORDER BY full_name"; $sql_result = mysql_query ($sql, $connection ) or die ('request "Could not execute SQL query" '.$sql); while ($row = mysql_fetch_assoc($sql_result)) { echo "<option value='".$row["full_name"]."'".($row["full_name"]==$_REQUEST["full_name"] ? " selected" : "").">".$row["full_name"]."</option>"; } ?> </select> <label>City</label> <select name="city"> <option value="">--</option> <?php $sql = "SELECT * FROM ".$SETTINGS["data_table"]." GROUP BY city ORDER BY city"; $sql_result = mysql_query ($sql, $connection ) or die ('request "Could not execute SQL query" '.$sql); while ($row = mysql_fetch_assoc($sql_result)) { echo "<option value='".$row["city"]."'".($row["city"]==$_REQUEST["city"] ? " selected" : "").">".$row["city"]."</option>"; } ?> </select> <input type="submit" name="button" id="button" value="Filter" /> </label> <a href="search.php"> reset</a> </form> <br /><br /> <table width="700" border="1" cellspacing="0" cellpadding="4"> <tr> <td width="90" bgcolor="#CCCCCC"><strong>From date</strong></td> <td width="95" bgcolor="#CCCCCC"><strong>To date</strong></td> <td width="159" bgcolor="#CCCCCC"><strong>Name</strong></td> <td width="191" bgcolor="#CCCCCC"><strong>Email</strong></td> <td width="113" bgcolor="#CCCCCC"><strong>City</strong></td> </tr> <?php if ($_REQUEST["city"]<>'') { $search_city = " AND city='".mysql_real_escape_string($_REQUEST["city"])."'"; } if ($_REQUEST["from"]<>'' and $_REQUEST["to"]<>'') { $sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE from_date >= '".mysql_real_escape_string($_REQUEST["from"])."' AND to_date <= '".mysql_real_escape_string($_REQUEST["to"])."'".$search_string.$search_city; } else if ($_REQUEST["from"]<>'') { $sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE from_date >= '".mysql_real_escape_string($_REQUEST["from"])."'".$search_string.$search_city; } else if ($_REQUEST["to"]<>'') { $sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE to_date <= '".mysql_real_escape_string($_REQUEST["to"])."'".$search_string.$search_city; } else { $sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE id>0".$search_string.$search_city; } $sql_result = mysql_query ($sql, $connection ) or die ('request "Could not execute SQL query" '.$sql); if (mysql_num_rows($sql_result)>0) { while ($row = mysql_fetch_assoc($sql_result)) { ?> <tr> <td><?php echo $row["from_date"]; ?></td> <td><?php echo $row["to_date"]; ?></td> <td><?php echo $row["full_name"]; ?></td> <td><?php echo $row["email"]; ?></td> <td><?php echo $row["city"]; ?></td> </tr> <?php } } else { ?> <tr><td colspan="5">No results found.</td> <?php } ?> </table> </body> </html> Quote Link to comment https://forums.phpfreaks.com/topic/259566-multiple-dropdowns-to-filter-query/ Share on other sites More sharing options...
mikemcg36 Posted March 23, 2012 Author Share Posted March 23, 2012 Sorry, I noticed some of this code is not necessary so I took some out and added a little myself. Here are the important lines if someone can combine the 2 select drop downs to query the table data. <?php if ($_REQUEST["city"]<>'') { $search_city = " AND city='".mysql_real_escape_string($_REQUEST["city"])."'"; } if ($_REQUEST["full_name"]<>'') { $search_name = " AND full_name='".mysql_real_escape_string($_REQUEST["full_name"])."'"; } if ($_REQUEST["from"]<>'') { $sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE from_date >= '".mysql_real_escape_string($_REQUEST["from"])."'".$search_string.$search_city; } else if ($_REQUEST["to"]<>'') { $sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE to_date <= '".mysql_real_escape_string($_REQUEST["to"])."'".$search_string.$search_city; } else { $sql = "SELECT * FROM ".$SETTINGS["data_table"]." WHERE id>0".$search_string.$search_city; } $sql_result = mysql_query ($sql, $connection ) or die ('request "Could not execute SQL query" '.$sql); ?> Quote Link to comment https://forums.phpfreaks.com/topic/259566-multiple-dropdowns-to-filter-query/#findComment-1330528 Share on other sites More sharing options...
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