pdoria Posted March 24, 2012 Share Posted March 24, 2012 Hi guys Since I'm not that good with regex I'm doing this quite the lame way ... <?php $string="[0:1]={1967,1968}"; $regex="#([[](.*)[]]=)#e"; $output=preg_replace($regex, '', $string); print ( $output . "<br/>" ); $search=array('{', '}'); $output=str_replace($search, "", $output); print ( $output ); ?> How can I do this in one pass using regex only? Thx in advance! Quote Link to comment Share on other sites More sharing options...
Psycho Posted March 24, 2012 Share Posted March 24, 2012 $regex = "#(\[[^\]]*\]=)|{|}#e"; $output = preg_replace($regex, '', $string); Quote Link to comment Share on other sites More sharing options...
pdoria Posted March 24, 2012 Author Share Posted March 24, 2012 Thx Psycho! and sorry to have posted in the wrong forum earlier... Quote Link to comment Share on other sites More sharing options...
ragax Posted March 24, 2012 Share Posted March 24, 2012 While fully in synch with Psycho about the method to match the content of the brackets, I'd like to offer a couple fine-tuning suggestions for the sake of "clean and compact": - the "e" modifier has no place in this regex - to match a single character out of a list, a character class is more efficient than alternations: [{}] rather than |{|} - no need for the parentheses $regex='#\[[^\]]*\]=|[{}]#'; Wishing you's a fun weekend. Quote Link to comment Share on other sites More sharing options...
pdoria Posted March 25, 2012 Author Share Posted March 25, 2012 Thx ragax! Yea ... lots of fun.. C++/Qt4, PHP, SQL ... ... .... two open IDE's (eclipse/kdevelop) ... Have a gr8 weekend too! Quote Link to comment Share on other sites More sharing options...
ragax Posted March 25, 2012 Share Posted March 25, 2012 Wow, that sounds full on! Good luck with your project. Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.