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php errer


raptor30506090

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$query = mysql_query("SELECT * FROM sub_nav WHERE subNav_ID=" . mysql_real_escape_string((int)$id));
					 $row = mysql_fetch_assoc($query);
					 $table =  $row['subNavName'];
					 // ******************************* This if statment controls the content ************************
					 if($row['show_hide'] == 1){
						                       $query = mysql_query("SELECT * FROM ('$table')");
											   while($row = mysql_fetch_assoc($query)){ ?>

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$query = mysql_query("SELECT * FROM ('$table')");

 

this is not what you had in your OP, and makes a big difference, as it's invalid syntax.

The way you wrote it in your OP is how it should be written, as long as $table is just a table name.

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output the SQL to see what it looks like:

 

$query = mysql_query("SELECT * FROM sub_nav WHERE subNav_ID=" . mysql_real_escape_string((int)$id));
$row = mysql_fetch_assoc($query);
$table =  $row['subNavName'];
if($row['show_hide'] == 1)
{
$sql = "SELECT * FROM $table";
$query = mysql_query($sql) or die(mysql_error() . '<br />' . $sql);
while($row = mysql_fetch_assoc($query))
{ ?>

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