pablo1988 Posted April 10, 2012 Share Posted April 10, 2012 I am getting the below error message: Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\Program Files (x86)\EasyPHP-5.3.9\www\a.php on line 78 The two issues are: 1. The red text I need to somehow use the DISTINCT function as it is duplicating a person for every skill they have. 2. The blue text is causing the error above, if I remove the join it works but assigns every possible skill to the person (because skill table and resource table are not joined). I therefore need the join there but without the error. My code is below: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> <title>Search Contacts</title> <style type="text/css" media="screen"> ul li{ list-style-type:none; } </style> </head> <p><body> <h3>Search Contacts Details</h3> <p>You may search either by first or last name</p> <form method="post" action="a.php?go" id="searchform"> <input type="text" name="name"> <input type="submit" name="submit" value="Search"> </form> <?php if(isset($_POST['submit'])){ if(isset($_GET['go'])){ if(preg_match("/^[ a-zA-Z]+/", $_POST['name'])){ $name=$_POST['name']; //connect to the database $db=mysql_connect ("127.0.0.1", "root", "") or die ('I cannot connect to the database because: ' . mysql_error()); //-select the database to use $mydb=mysql_select_db("resource matrix"); //-query the database table $sql="SELECT * FROM ((resource l inner join resource_skill ln on l.Resource_ID = ln.Resource_ID) inner join skill n on ln.Skill_ID = n.Skill_ID) WHERE First_Name LIKE '%" . $name . "%' OR Last_Name LIKE '%" . $name ."%' OR Skill_Name LIKE '%" . $name ."%'"; //-run the query against the mysql query function $result=mysql_query($sql); //-create while loop and loop through result set while($row=mysql_fetch_array($result)){ $First_Name =$row['First_Name']; $Last_Name=$row['Last_Name']; $Resource_ID=$row['Resource_ID']; //-display the result of the array echo "<ul>\n"; echo "<li>" . "<a href=\"a.php?id=$Resource_ID\">" .$First_Name . " " . $Last_Name . "</a></li>\n"; echo "</ul>"; } } else{ echo "<p>Please enter a search query</p>"; } } } //end of our letter search script if(isset($_GET['id'])){ $contactid=$_GET['id']; //connect to the database $db=mysql_connect ("127.0.0.1", "root", "") or die ('I cannot connect to the database because: ' . mysql_error()); //-select the database to use $mydb=mysql_select_db("resource matrix"); //-query the database table $sql="SELECT * FROM ((resource l inner join resource_skill ln on l.Resource_ID = ln.Resource_ID) inner join skill n on ln.Skill_ID = n.Skill_ID) WHERE Resource_ID=" . $contactid; //-run the query against the mysql query function $result=mysql_query($sql); //-create while loop and loop through result set while($row=mysql_fetch_array($result)){ $First_Name =$row['First_Name']; $Last_Name=$row['Last_Name']; $Mobile_Number=$row['Mobile_Number']; $Email_Address=$row['Email_Address']; $Level=$row['Level']; $Security_Cleared=$row['Security_Cleared']; $Contract_Type=$row['Contract_Type']; $Contract_Expiry=$row['Contract_Expiry']; $Day_Rate=$row['Day_Rate']; $Post_Code=$row['Post_Code']; $Skill_Name=$row['Skill_Name']; //-display the result of the array echo "<ul>\n"; echo "<li>" . $First_Name . " " . $Last_Name . "</li>\n"; echo "<li>" . $Mobile_Number . "</li>\n"; echo "<li>" . "<a href=mailto:" . $Email_Address . ">" . $Email_Address . "</a></li>\n"; echo "<li>" . $Level . "</li>\n"; echo "<li>" . $Security_Cleared . "</li>\n"; echo "<li>" . $Contract_Type . "</li>\n"; echo "<li>" . $Contract_Expiry . "</li>\n"; echo "<li>" . $Day_Rate . "</li>\n"; echo "<li>" . $Post_Code . "</li>\n"; echo "<li>" . $Skill_Name . "</li>\n"; echo "</ul>"; } } ?> </body> </html> Quote Link to comment https://forums.phpfreaks.com/topic/260674-warning-mysql_fetch_array-expects-parameter-1-to-be-resource-boolean-given-i/ Share on other sites More sharing options...
yami007 Posted April 10, 2012 Share Posted April 10, 2012 probably a query error...you might use mysql_error Quote Link to comment https://forums.phpfreaks.com/topic/260674-warning-mysql_fetch_array-expects-parameter-1-to-be-resource-boolean-given-i/#findComment-1336025 Share on other sites More sharing options...
pablo1988 Posted April 10, 2012 Author Share Posted April 10, 2012 thanks yami007, how would I do that? I don't have much knowledge with mysql. Quote Link to comment https://forums.phpfreaks.com/topic/260674-warning-mysql_fetch_array-expects-parameter-1-to-be-resource-boolean-given-i/#findComment-1336040 Share on other sites More sharing options...
AyKay47 Posted April 10, 2012 Share Posted April 10, 2012 my money is on an ambiguity issue with Resource_ID, but add this to the query: $sql="SELECT * FROM resource l inner join resource_skill ln on l.Resource_ID = ln.Resource_ID inner join skill n on ln.Skill_ID = n.Skill_ID WHERE Resource_ID=" . $contactid; //-run the query against the mysql query function $result=mysql_query($sql) or die(mysql_error() . '<br />' . $sql); post the results. Quote Link to comment https://forums.phpfreaks.com/topic/260674-warning-mysql_fetch_array-expects-parameter-1-to-be-resource-boolean-given-i/#findComment-1336041 Share on other sites More sharing options...
pablo1988 Posted April 10, 2012 Author Share Posted April 10, 2012 Thanks AyKay47, see results below: Column 'Resource_ID' in where clause is ambiguous SELECT * FROM resource l inner join resource_skill ln on l.Resource_ID = ln.Resource_ID inner join skill n on ln.Skill_ID = n.Skill_ID WHERE Resource_ID=4 Quote Link to comment https://forums.phpfreaks.com/topic/260674-warning-mysql_fetch_array-expects-parameter-1-to-be-resource-boolean-given-i/#findComment-1336048 Share on other sites More sharing options...
AyKay47 Posted April 10, 2012 Share Posted April 10, 2012 yah that's what I was thinking. In the WHERE clause you specify Resource_ID without a table identifier attached. A table identifier is needed from the table it's coming from. Quote Link to comment https://forums.phpfreaks.com/topic/260674-warning-mysql_fetch_array-expects-parameter-1-to-be-resource-boolean-given-i/#findComment-1336055 Share on other sites More sharing options...
pablo1988 Posted April 10, 2012 Author Share Posted April 10, 2012 Do you mean just change Resource_ID to resource.Resource_ID (resource being one of the tables Resource_ID is located)? I have added that but get the below error: Unknown column 'resource.Resource_ID' in 'where clause' SELECT * FROM resource l inner join resource_skill ln on l.Resource_ID = ln.Resource_ID inner join skill n on ln.Skill_ID = n.Skill_ID WHERE resource.Resource_ID=4 Is that what you mean by table identifier? Thanks for your help Quote Link to comment https://forums.phpfreaks.com/topic/260674-warning-mysql_fetch_array-expects-parameter-1-to-be-resource-boolean-given-i/#findComment-1336058 Share on other sites More sharing options...
AyKay47 Posted April 10, 2012 Share Posted April 10, 2012 you have specified an alias for the tbl resource ( l ), use that. l.Resource_ID Quote Link to comment https://forums.phpfreaks.com/topic/260674-warning-mysql_fetch_array-expects-parameter-1-to-be-resource-boolean-given-i/#findComment-1336061 Share on other sites More sharing options...
pablo1988 Posted April 10, 2012 Author Share Posted April 10, 2012 I see, that has done it! Thanks a lot! Now for the next challenge...getting rid of the duplicates. The highlighted RED text below duplicates names dependant on the number of skills they have assigned to them. -> I need to just show the First and Last Name once. The highlighted BLUE text below duplicates all of the persons details for each skill. -> I need to show the person details once other than the skill which I need to list all assigned to the person. I'm sure it's some use of DISTINCT but not sure where and how. Thanks again AyKay47 <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1"> <title>Search Contacts</title> <style type="text/css" media="screen"> ul li{ list-style-type:none; } </style> </head> <p><body> <h3>Search Contacts Details</h3> <p>You may search either by first or last name</p> <form method="post" action="a.php?go" id="searchform"> <input type="text" name="name"> <input type="submit" name="submit" value="Search"> </form> <?php if(isset($_POST['submit'])){ if(isset($_GET['go'])){ if(preg_match("/^[ a-zA-Z]+/", $_POST['name'])){ $name=$_POST['name']; //connect to the database $db=mysql_connect ("127.0.0.1", "root", "") or die ('I cannot connect to the database because: ' . mysql_error()); //-select the database to use $mydb=mysql_select_db("resource matrix"); //-query the database table $sql="SELECT * FROM ((resource l inner join resource_skill ln on l.Resource_ID = ln.Resource_ID) inner join skill n on ln.Skill_ID = n.Skill_ID) WHERE First_Name LIKE '%" . $name . "%' OR Last_Name LIKE '%" . $name ."%' OR Skill_Name LIKE '%" . $name ."%'"; //-run the query against the mysql query function $result=mysql_query($sql); //-create while loop and loop through result set while($row=mysql_fetch_array($result)){ $First_Name =$row['First_Name']; $Last_Name=$row['Last_Name']; $Resource_ID=$row['Resource_ID']; //-display the result of the array echo "<ul>\n"; echo "<li>" . "<a href=\"a.php?id=$Resource_ID\">" .$First_Name . " " . $Last_Name . "</a></li>\n"; echo "</ul>"; } } else{ echo "<p>Please enter a search query</p>"; } } } //end of our letter search script if(isset($_GET['id'])){ $contactid=$_GET['id']; //connect to the database $db=mysql_connect ("127.0.0.1", "root", "") or die ('I cannot connect to the database because: ' . mysql_error()); //-select the database to use $mydb=mysql_select_db("resource matrix"); $sql="SELECT * FROM resource l inner join resource_skill ln on l.Resource_ID = ln.Resource_ID inner join skill n on ln.Skill_ID = n.Skill_ID WHERE l.Resource_ID=" . $contactid; //-run the query against the mysql query function $result=mysql_query($sql) or die(mysql_error() . '<br />' . $sql); //-create while loop and loop through result set while($row=mysql_fetch_array($result)){ $First_Name =$row['First_Name']; $Last_Name=$row['Last_Name']; $Mobile_Number=$row['Mobile_Number']; $Email_Address=$row['Email_Address']; $Level=$row['Level']; $Security_Cleared=$row['Security_Cleared']; $Contract_Type=$row['Contract_Type']; $Contract_Expiry=$row['Contract_Expiry']; $Day_Rate=$row['Day_Rate']; $Post_Code=$row['Post_Code']; $Skill_Name=$row['Skill_Name']; //-display the result of the array echo "<ul>\n"; echo "<li>" . $First_Name . " " . $Last_Name . "</li>\n"; echo "<li>" . $Mobile_Number . "</li>\n"; echo "<li>" . "<a href=mailto:" . $Email_Address . ">" . $Email_Address . "</a></li>\n"; echo "<li>" . $Level . "</li>\n"; echo "<li>" . $Security_Cleared . "</li>\n"; echo "<li>" . $Contract_Type . "</li>\n"; echo "<li>" . $Contract_Expiry . "</li>\n"; echo "<li>" . $Day_Rate . "</li>\n"; echo "<li>" . $Post_Code . "</li>\n"; echo "<li>" . $Skill_Name . "</li>\n"; echo "</ul>"; } } ?> </body> </html> Quote Link to comment https://forums.phpfreaks.com/topic/260674-warning-mysql_fetch_array-expects-parameter-1-to-be-resource-boolean-given-i/#findComment-1336065 Share on other sites More sharing options...
AyKay47 Posted April 10, 2012 Share Posted April 10, 2012 http://dev.mysql.com/doc/refman/5.0/en/distinct-optimization.html Quote Link to comment https://forums.phpfreaks.com/topic/260674-warning-mysql_fetch_array-expects-parameter-1-to-be-resource-boolean-given-i/#findComment-1336068 Share on other sites More sharing options...
pablo1988 Posted April 10, 2012 Author Share Posted April 10, 2012 How do you apply the distinct function with SELECT * ? I know how to use it for SELECT DISTINCT First_Name etc. But as I am using SELECT * for both queries, I'm not sure I would apply it the code. Quote Link to comment https://forums.phpfreaks.com/topic/260674-warning-mysql_fetch_array-expects-parameter-1-to-be-resource-boolean-given-i/#findComment-1336072 Share on other sites More sharing options...
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