fredrikrob Posted April 14, 2012 Share Posted April 14, 2012 Hi, I have some problem in ajax like i am not able to retrieve data through Ajax. Please look at the attachment pic to better understand the scenario. . Here are three fields first one will go with State, second will go with the city within the state and third one is for the market's or showroom within the city. I can easily retrive the data till first 2 option. Like if i select the State A and then i can see all the cities under the state A but i am not able to get the output in the market section. As Ajax query have only one response variable. I have spent lot's of hour in this and now have give up. Please help me in this. I am attaching the both php and files to get it clear. here is the main desiging file: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <script type="text/javascript"> function Action(link,md) { var obj,url; url="dcode.php?mode="+md+"&id="+link; try { obj=new XMLHttpRequest(); } catch(e) { try { obj=new ActivexObject("Microsoft.XMLHTTP"); } catch(e) { alert(e); } } obj.open("GET",url,true); obj.send(null); obj.onreadystatechange=function() { if(obj.readyState==4) { var res=obj.responseText; alert(res); document.getElementById("city").innerHTML=res; } } } </script> <? ?> </head> <body> <form action="dcode.php" method="get"> <table width="200" border="1" align="center"> <tr> <th scope="row"><label> <select name="state" id="state" style="width:150px;" onchange="Action(this.value,'state')"> <? mysql_connect("localhost","root","") or die("check server"); mysql_select_db("students")or die("check database"); $str="select sno,sname from state"; $rs=mysql_query($str); while(list($scode,$stname)=mysql_fetch_array($rs)) { echo "<option value='$scode'>$stname</option>"; } ?> </select> </label></th> </tr> <tr> <th scope="row"><label> <select name="city" id="city" style="width:150px;" onchange="Action(this.value,'city')"> <option value="city">Select city</option> <? $str="SELECT citycode,cityname FROM city WHERE statecode IN ( SELECT statecode FROM city JOIN state ON city.statecode = $id )"; $rs=mysql_query($str); while(list($citycode,$cityname)=mysql_fetch_array($rs)) { echo "<option value='$citycode'>$cityname</option>"; } ?> </select> </label></th> </tr> <tr> <th scope="row"><select name="market" id="market" style="width:150px;"> <option value="market">Select Market</option> <? $str="SELECT citycode,cityname FROM city WHERE statecode IN ( SELECT statecode FROM city JOIN state ON city.statecode = $id )"; $rs=mysql_query($str); while(list($citycode,$cityname)=mysql_fetch_array($rs)) { echo "<option value='$citycode'>$cityname</option>"; } ?> </select></th> </tr> </table> </form> <script type="text/javascript"> Action(101,'state'); </script> </body> </html> and here is the main Code file where i have written php query to get the result: <? mysql_connect("localhost","root","") or die("check server"); mysql_select_db("students")or die("check database"); if($_REQUEST["mode"]==state) { $id=$_REQUEST["id"]; $str="SELECT citycode,cityname FROM city WHERE statecode IN ( SELECT statecode FROM city JOIN state ON city.statecode = $id)"; $rs=mysql_query($str); while(list($citycode,$cityname)=mysql_fetch_array($rs)) { echo "<option value='$citycode'>$cityname</option>"; } } ?> Quote Link to comment https://forums.phpfreaks.com/topic/260918-need-help-in-ajax-with-php/ Share on other sites More sharing options...
sunfighter Posted April 14, 2012 Share Posted April 14, 2012 Your query does not look healthy $str="SELECT citycode,cityname FROM city WHERE statecode IN ( SELECT statecode FROM city JOIN state ON city.statecode = $id)"; This is what I think you want $str="SELECT citycode, cityname FROM city WHERE statecode = $id"; And you should has something in your first dropdown. Yours is empty. And I would not use 'action' as the name of a function. I'm sure it's a reserved word, but too lasy to look it up. Try "get_select" instead. Quote Link to comment https://forums.phpfreaks.com/topic/260918-need-help-in-ajax-with-php/#findComment-1337316 Share on other sites More sharing options...
fredrikrob Posted April 17, 2012 Author Share Posted April 17, 2012 Your query does not look healthy $str="SELECT citycode,cityname FROM city WHERE statecode IN ( SELECT statecode FROM city JOIN state ON city.statecode = $id)"; This is what I think you want $str="SELECT citycode, cityname FROM city WHERE statecode = $id"; And you should has something in your first dropdown. Yours is empty. And I would not use 'action' as the name of a function. I'm sure it's a reserved word, but too lasy to look it up. Try "get_select" instead. Thanks for the reply. Well i had a message code in my file before but i had issue in Ajax and javascript as i was unable to print the double result. With the help of ajax i was getting one 2 response one for city and one for market dropdown menu. But i had only one id selected to print the result. For that i have used if condition and now it's working. Here is the code : var res=obj.responseText; if(md=='city') { document.getElementById("market").innerHTML=res; } else { document.getElementById("city").innerHTML=res; } But now i cant get 100% good result like i am not able to get the result on third menu as i use to change value in the first menu. Hop you got my point. Thanks. Quote Link to comment https://forums.phpfreaks.com/topic/260918-need-help-in-ajax-with-php/#findComment-1338137 Share on other sites More sharing options...
sunfighter Posted April 17, 2012 Share Posted April 17, 2012 OK I guess I don't know what you want. I see three drop down menus that you want populated, right? I don't know what you want in the top dropdown because it is blank. But think it's the state. Right? The second dropdown has 'select city' in it and I thought you needed to find the cities that came from the first dropdown choice. Which should be the state or as you call it statecode and that came from the first or top dropdown. Is that right? And then you want to get the market and put that in the select market dropdown, the third one. Is that right? And where (table and column) is that info and what is the city column needed for that extraction? I gave you the query to get the second dropdown information after the state was picked in the first. You say this don't work? Your not getting the city names? Quote Link to comment https://forums.phpfreaks.com/topic/260918-need-help-in-ajax-with-php/#findComment-1338197 Share on other sites More sharing options...
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