fsockopen

[sanchez77]

I am trying to open a Unix server and was wondering how would you return what the Unix server is saying, ie the prompt? Here is the code I was using after reading the php.net. The $call variable is my attempt at reading the server and have it return what it says.

 

I do have a connection to the server cause if I change the address or port number, i have the error in the log file saying the address refused the connection.

 

Any help/insight is really appreciated. Thanks

 

<?php

$host = "127.0.0.1";
$port = 9595;

$fp = stream_socket_client("tcp://".$host.":".$port."", $errno, $errstr, 30);

$call = fgets($fp);

echo $call;

fclose($fp);
?>

[sanchez77]

sorry, code on the brain. It's really not fsockopen, it's stream_socket_client, but i tried fsockopen as well

 

<?php
$host = "127.0.0.1";
$port = 9595;

$fp = fsockopen($host, $port, $errno, $errstr, 30);

$call = fgets($fp);

echo $call;

fclose($fp);

?>