alexmark Posted April 27, 2012 Share Posted April 27, 2012 Hi all I have a MySQL data base that is saving information from a form. One the form a user can add a business name which is text and a logo if they have one. Now on my web page I want to beabe to display the picture if present if not I would like it to display the business name. How do I do this please. I know how to conect to DB etc just having problems getting my head around this problem. Link to comment https://forums.phpfreaks.com/topic/261730-display-text-if-picture-not-present/ Share on other sites More sharing options...
plznty Posted April 27, 2012 Share Posted April 27, 2012 $mysqlqueryresult = ''; if ( empty($mysqlqueryresult) ) { // For default image // echo '<img src="defaultimage.jpg" />'; // For Text // echo $theQueryToGetText; } else { echo '<img src="theUrlOfTheImage.jpg" />'; } Some code would be more useful for me or others to assist you. Link to comment https://forums.phpfreaks.com/topic/261730-display-text-if-picture-not-present/#findComment-1341257 Share on other sites More sharing options...
alexmark Posted April 27, 2012 Author Share Posted April 27, 2012 What code would you like? Link to comment https://forums.phpfreaks.com/topic/261730-display-text-if-picture-not-present/#findComment-1341276 Share on other sites More sharing options...
QuickOldCar Posted April 28, 2012 Share Posted April 28, 2012 http://php.net/manual/en/function.file-exists.php if(file_exists($mysql_image)){ echo "<img src='$mysql_image' />"; } else { echo $mysql_bus_name; } Link to comment https://forums.phpfreaks.com/topic/261730-display-text-if-picture-not-present/#findComment-1341285 Share on other sites More sharing options...
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