Problem with my preg_replace

[Davikore]

Hi,

 

I am trying to replace an image inside an html  file using this:

 

The file contains this:

 

<img class="uiProfilePhoto headerTinymanPhoto uiProfilePhotoLarge img" src="http://profile.ak.fbcdn.net/hprofile-ak-snc4/370282_100003830116243_1299179951_q.jpg" alt="" />

 

And I want to replace it with this:

 

<img class="uiProfilePhoto headerTinymanPhoto uiProfilePhotoLarge img" src="http://example.com/FC.jpg" alt="" />

 

This is what I have tried:

 

$URLSearchString = " a-zA-Z0-9\:\/\-\?\&\.\=\_\~\#\'";

$page_html = preg_replace("#headerTinymanPhoto uiProfilePhotoLarge img\" src=\"($URLSearchString)\"#", 'http://example.com/FC.jpg', $page_html);  

 

But its not working.

 

Can anyone see what I have done wrong ?

 

Is preg_replace the correct tool to use ?

 

Thanks.

 

 

 

.

[xyph]

You want to capture everything before $URLSearchString. Then you can use

 

\1http://example.com/FC.jpg"

 

http://php.net/manual/en/function.preg-replace.php

 

View the source of your web page to see what's going wrong.

[Psycho]

Your search string is looking for the literal string " a-zA-Z0-9\:\/\-\?\&\.\=\_\~\#\'" - NOT those characters. You could put those characters in a character class to do what you intended [ a-zA-Z0-9\:\/\-\?\&\.\=\_\~\#\], but there is a much better way. Use a negative character class to look for any characters that are not a double quote. Also you should also "capture" the text before the replacement so you can put it back in. Otherwise you will lose the class parameter text (unless you were to hard code it in the replacement).

 

$pattern = '#(headerTinymanPhoto uiProfilePhotoLarge img" src=")([^"]*)#';
$replacement = '${1}http://example.com/FC.jpg';

$page_html = preg_replace($pattern, $replacement, $page_html);