Server is up or not

[NLT]

What would be the best way to return:

One image (let's say, green.png) if the specified website is up

Second image (let's say, red.png) if the specified website is down

Third image (let's say, orange.png) if the website is slow.

 

Would the best option be to use file_get_contents?

 

Or a exec

[3cool4school]

by return are you sending the value somewhere, or just trying to display it?

[NLT]

Just displaying it. Well, show an image relevant to whether the server is up, down, or slow.

[NLT]

Actually, I've got another idea.

Have one image, but with 3 different light images obviously, and change the image (imagename.jpg) to whatever is relevant, but keeping the imagename.jpg file name the same. If that's possible, that is.

[3cool4school]

Throw in the correct image location lbut you have to have your conditions so something along these lines

 

<?php  

$theimage = "";

if (SERVER UP CONDITION){

$theimage .= "<img src ='green.png' />"; 

}
elseif (SERVER DOWN CONDITION){

$theimage .= "<img src ='red.png' />"; 

}
elseif (SERVER SLOW CONDITION){

$theimage .= "<img src ='orange.png' />"; 

}

?>

 

 

then wherever you want to display is (I would use a div so you can control sizing and location etc)

 

<div class ="serverstatus"> <?php echo $theimage; ?> </div>

 

 

I'm not sure if you needed help with the actual figuring out if the server was down up or slow

 

[NLT]

Would there be a way to have it all in one image?

[xyph]

There's a way to have it in a single image, but you'd then need to use CSS to 'change' the image

http://yensdesign.com/tutorials/masteringbackgroundposition/