Scooby-Doo Posted May 25, 2012 Share Posted May 25, 2012 I am struggling again, right do my best to explain got a dropdown with 3 selections..ie <form action="prices.php" method="post" name="prices"> <select name="dropdowns" class="selectionbox" value="options" id="selection"> <option value="ns" selected="selected">Please Select</option> <option value="selection1.php">Selection 1</option> <option value="selection2.php">Selection 2</option> <option value="selection3.php">Selection 3</option> </select> When the user clicks on the "Get Prices" button it will open prices.php....but on prices.php I want to have an include("selection1.php") or (selection2.php) etc depending on what the user selected in the drop down box. Now dont laugh at my code but I have done this but dont know how to make it just chose one at the minute it is just including both of them <?php $selection1 = isset($_POST['selection1']) ? $_POST["selection1"] : ""; $selection2 = isset($_POST['selection2']) ? $_POST["selection2"] : ""; if ($selection1); include ("selection1.php"); if ($selection2); include ("selection2.php"); ?> Any help much appreciated...and as you can probably see im new to php Link to comment https://forums.phpfreaks.com/topic/263144-dropdown-selection-open-different-page/ Share on other sites More sharing options...
Drummin Posted May 25, 2012 Share Posted May 25, 2012 Not sure if this will help. <html> <body> <?php isset($_POST['dropdowns']) ? include($_POST["dropdowns"]) : ""; ?> <form action="prices.php" method="post" name="prices"> <select name="dropdowns" class="selectionbox" value="options" id="selection"> <option value="ns" selected="selected">Please Select</option> <option value="selection1.php">Selection 1</option> <option value="selection2.php">Selection 2</option> <option value="selection3.php">Selection 3</option> </select> <input type="submit" value="Submit" /> </form> </body> </html> Link to comment https://forums.phpfreaks.com/topic/263144-dropdown-selection-open-different-page/#findComment-1348677 Share on other sites More sharing options...
Psycho Posted May 25, 2012 Share Posted May 25, 2012 Sorry, but I have to advise against using Drummin's solution. You should never use values from user submitted data directly in an include statement. You need to validate it first. $includeValue = isset($_POST['dropdowns']) ? $_POST['dropdowns'] : false; switch($includeValue) { case 'selection1.php': case 'selection2.php': case 'selection3.php': include($includeValue); break; default: include('selection1.php'); } Link to comment https://forums.phpfreaks.com/topic/263144-dropdown-selection-open-different-page/#findComment-1348678 Share on other sites More sharing options...
Scooby-Doo Posted May 25, 2012 Author Share Posted May 25, 2012 Thank you Psycho worked a treat....Just one more question, I have used your code so it includes() the selected pages..ie $inspection = isset($_POST['inspections']) ? $_POST['inspections'] : false; $delivery = isset($_POST['delivery']) ? $_POST['delivery'] : false; switch($inspection) { case 'basic.php': case 'platinum.php': case 'accident.php': include($inspection); break; default: include('basic.php'); } ?> <?php switch($delivery) { case 'delivery.php': case 'nodelivery.php': include($delivery); break; default: include('nodelivery.php'); } ?> Would it be difficult to put a value to each selection...for arguments sake if someone selected Platinum Inspection £10 with no delivery £0 it would calculate the two prices and place in a total inspection + delivery Hope that makes sense Link to comment https://forums.phpfreaks.com/topic/263144-dropdown-selection-open-different-page/#findComment-1348681 Share on other sites More sharing options...
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