Please help passing a PHP url parameter

[lingo5]

Hi,

I have a "tell a friend script" that opens a popup using javascript.

The script posts opens a popup containig a form like this:

 

var source = "friend_form.php";

 

My problem is that I need to also pass a URL parameter like so:

 

var source = "friend_form.php?id_property='<?php echo $row_properties_RS['id_property]?>'";

 

but it doesn't seem to work as the popup does not get the id_property passed.

 

I know I'm doing something wrong but can't figure it out

 

Thanks

[lingo5]

Hi again,

I've tried this:

<?php 
$myVar="friend_form.php?id_property=$row_properties_RS['id_property]";
?>

 

and then added this to the JS:

 

var source = '<?php echo $myVar ;?>';

 

but get this error:

 

Parse error: parse error, expecting `T_STRING' or `T_VARIABLE' or `T_NUM_STRING' in C:\wamp\www\mysite\index.php on line 89

 

being line 89 this:

 

$myVar="friend_form.php?id_property=$row_properties_RS['id_property]";

 

:confused: :confused: :confused:

[Alex]

Try:

 

$myVar="friend_form.php?id_property=" . $row_properties_RS['id_property'];

[lingo5]

Thanks Alex,

well at least this is passing a URL parameter...the problem is it always passes the same one (the id of the first record on my DB)

:confused:

[lingo5]

OK, here's the button you press to open the "tlla frind" popup

 

 <td width="6%"><a class="modal" href="javascript:void(0);"><img src="img/iconos/enviar_amigo.gif" width="21" height="17" border="0"  class="fixedTip"  title="enviar a un amigo" /></a></td>

 

this is my recordset and the $myVar variable that I use in the JS:

 

mysql_select_db($database_MySQLconnect, $MySQLconnect);
$query_destacadas_RS = "SELECT * FROM t_propiedades WHERE destacada = 1";
$destacadas_RS = mysql_query($query_destacadas_RS, $MySQLconnect) or die(mysql_error());
$row_destacadas_RS = mysql_fetch_assoc($destacadas_RS);
$totalRows_destacadas_RS = mysql_num_rows($destacadas_RS);

$myVar="friend_form.php?id_propiedad=". $row_destacadas_RS['id_propiedad'];

 

and this is the JS:

 

<script language="javascript">

  $(document).ready(function() {

    
    var source = '<?php echo $myVar ;?>';
    var width = 400;
    var align = "center";
    var top = 100;
    var padding = 10;
    var backgroundColor = "#FFFFFF";
    var borderColor = "#FFD200";
    var borderWeight = 4;
    var borderRadius = 5;
    var fadeOutTime = 300;
    var disableColor = "#666666";
    var disableOpacity = 40;
    var loadingImage = "images/loading.gif";

    //This method initialises the modal popup
    $(".modal").click(function() {

        modalPopup( align,
	    top,
	    width,
	    padding,
	    disableColor,
	    disableOpacity,
	    backgroundColor,
	    borderColor,
	    borderWeight,
	    borderRadius,
	    fadeOutTime,
	    source,
	    loadingImage );

    });	

    //This method hides the popup when the escape key is pressed
    $(document).keyup(function(e) {
        if (e.keyCode == 27) {
            closePopup(fadeOutTime);
        }
    });

  });

</script>

 

and still all I get is the same variable passed to  friend_form.php.....

 

any reasons why this is only passing the id_propiedad of the first record on my DB??

 

Thanks