A cleaner way to achieve JSON

[hackalive]

Hi Guys,

 

Currently om piecing together my JSON in a rather crap way (for want of a better word)

 

			$id = "1"; // CALLED FROM USERS TABLE
			$first_name = "John"; // CALLED FROM USERS TABLE
			$last_name = "Smith"; // CALLED FROM USERS TABLE
			$name = $first_name.' '.$last_name;
			$username = "jsmith"; // CALLED FROM USERS TABLE
			$birthday = "01/01/2001"; // CALLED FROM USERS TABLE
			$gender = "male"; // CALLED FROM USERS TABLE

			$hometownid = "10"; // CALLED FROM USERS TABLE
			$hometown = "New York"; // FROM ANOTHER TABLE THAT REFS THE ID

			$locationid = "11"; // CALLED FROM USERS TABLE
			$location = "London"; // FROM ANOTHER TABLE THAT REFS THE ID

			$output1 = array('id'=>$id,'name'=>$name,'first_name'=>$first_name,'last_name'=>$last_name,'usernmae'=>$username,'birthday'=>$birthday,'gender'=>$gender,'hometown'=>array('id'=>$hometownid,'name'=>$hometown),'location'=>array('id'=>$locationid,'name'=>$location));

			$output = json_encode($output1);

 

How could I create the $output1 in a cleaner and neater way?

 

Cheers

[devWhiz]

	
$output1['id'] = $id;
$output1['name'] = $name;
$output1['first_name'] = $first_name;
$output1['last_name'] = $last_name;
$output1['username'] = $username;
$output1['birthday'] = $birthday;
$output1['gender'] = $gender;
$output1['hometown']['id'] = $hometownid;
$output1['hometown']['name'] = $hometown;
$output1['location']['id'] = $locationid;
$output1['location']['name'] = $location;

[hackalive]

I know doing

 

$result = $mysqli->query($query);
$array = $result->fetch_assoc();
json_encode($array)

 

is the nicest way to do it if data only comes from one table - but how to do it from multiple sources.

[PFMaBiSmAd]

Your goal would be for your query to return an array with the keys and values that you need. Then simply json_encode that array.

 

  Quote

but how to do it from multiple sources

 

You should be using one joined query to get all the related data in one query. Without more specific information from you, not possible to directly help.

[hackalive]

At the moment this is my total code:

 

		$queryA = "SELECT * FROM `user` WHERE `id`='3'";
		$resultA = $mysqli->query($queryA);
		$arrayA = $resultA->fetch_assoc();

		if($arrayA['id'])
		{
			$id = $arrayA['id']; // CALLED FROM USERS TABLE
			$first_name = $arrayA['first_name']; // CALLED FROM USERS TABLE
			$last_name = $arrayA['last_name']; // CALLED FROM USERS TABLE
			$name = $first_name.' '.$last_name;
			$username = $arrayA['username']; // CALLED FROM USERS TABLE
			$birthday = "01/01/2001"; // CALLED FROM USERS TABLE
			$gender = $arrayA['gender']; // CALLED FROM USERS TABLE

			$hometownid = $arrayA['hometown']; // CALLED FROM USERS TABLE
			$queryB = "SELECT * FROM `locations` WHERE `id`='$hometownid'";
			$resultB = $mysqli->query($queryB);
			$arrayB = $resultB->fetch_assoc();
			$hometown = $arrayB['name']; // FROM ANOTHER TABLE THAT REFS THE ID

			$locationid = $arrayA['location']; // CALLED FROM USERS TABLE
			$queryC = "SELECT * FROM `locations` WHERE `id`='$locationid'";
			$resultC = $mysqli->query($queryC);
			$arrayC = $resultC->fetch_assoc();
			$hometown = $arrayC['name']; // FROM ANOTHER TABLE THAT REFS THE ID

			$output = array('id'=>$id,'name'=>$name,'first_name'=>$first_name,'last_name'=>$last_name,'usernmae'=>$username,'birthday'=>$birthday,'gender'=>$gender,'hometown'=>array('id'=>$hometownid,'name'=>$hometown),'location'=>array('id'=>$locationid,'name'=>$location));

			$output = json_encode($output);

			echo $output;
		}

 

Hopefully this is of some help to you PFMaBiSmAd

 

 

(PS: I do need the location & hometown etc to format as those "sub" arrays).

[hackalive]

BUMP