stratos Posted June 14, 2012 Share Posted June 14, 2012 Here is my code if (!empty($vsmallimg[$x])) echo "<a href='vehicle.php?vid=".$vid[$x]."'><table width='980' onMouseOver=".this.bgColor='#0E05B1';" onMouseOut='this.bgColor="transparent';">...(rest of table format is fine)</a> I just added the onmouseover to change the background colour of the table, without it everything works fine. But now it is giving me problems because of the double quotation marks which terminates the echo command.. Are there any ways around this problem? I just need to change the background colour or background image of the table onmouseover. Thanks for your time Link to comment https://forums.phpfreaks.com/topic/264171-error-printing-in-a-echo-command/ Share on other sites More sharing options...
AMcHarg Posted June 14, 2012 Share Posted June 14, 2012 \" Link to comment https://forums.phpfreaks.com/topic/264171-error-printing-in-a-echo-command/#findComment-1353775 Share on other sites More sharing options...
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