Jump to content

New to Ajax question


zimminy

Recommended Posts

Been coding in PHP for years, using and working with Javascript but not writing it from scratch at all. Trying to get a handle on how to Ajax and javascript for a project this week. Have a question.

 

This works fine, tested it on my host, it's from w3schools:

<!DOCTYPE html>
<html>
<head>
<script type="text/javascript">
function showCustomer(str)
{
var xmlhttp;    
if (str=="")
  {
  document.getElementById("txtHint").innerHTML="";
  return;
  }
if (window.XMLHttpRequest)
  {// code for IE7+, Firefox, Chrome, Opera, Safari
  xmlhttp=new XMLHttpRequest();
  }
else
  {// code for IE6, IE5
  xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
xmlhttp.onreadystatechange=function()
  {
  if (xmlhttp.readyState==4 && xmlhttp.status==200)
    {
    document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
    }
  }
xmlhttp.open("GET","ajaxtestpost.php?vv="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>

<form action=""> 
<select name="customers" onchange="showCustomer(this.value)">
<option value="1">1</option>
<option value="2">2</option>
<option value="3">3</option>
</select>
</form>
<br />
<div id="txtHint">Customer info will be listed here...</div>

</body>
</html>

 

 

 

Question is this:

How do I add to the form this:

<input type="hidden" name="foodid" id="foodid" value="5">

 

and have it end up populating the info here, so that my ajaxtestpost.php page can use it?:

xmlhttp.open("GET","ajaxtestpost.php?foodid="+str2"&&vv="+str,true);

 

The things I have tried did not work, I am a little lost...

 

Thanks much!!!

 

Link to comment
https://forums.phpfreaks.com/topic/264812-new-to-ajax-question/
Share on other sites

Archived

This topic is now archived and is closed to further replies.

×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.