zimminy Posted June 26, 2012 Share Posted June 26, 2012 Been coding in PHP for years, using and working with Javascript but not writing it from scratch at all. Trying to get a handle on how to Ajax and javascript for a project this week. Have a question. This works fine, tested it on my host, it's from w3schools: <!DOCTYPE html> <html> <head> <script type="text/javascript"> function showCustomer(str) { var xmlhttp; if (str=="") { document.getElementById("txtHint").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("txtHint").innerHTML=xmlhttp.responseText; } } xmlhttp.open("GET","ajaxtestpost.php?vv="+str,true); xmlhttp.send(); } </script> </head> <body> <form action=""> <select name="customers" onchange="showCustomer(this.value)"> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> </select> </form> <br /> <div id="txtHint">Customer info will be listed here...</div> </body> </html> Question is this: How do I add to the form this: <input type="hidden" name="foodid" id="foodid" value="5"> and have it end up populating the info here, so that my ajaxtestpost.php page can use it?: xmlhttp.open("GET","ajaxtestpost.php?foodid="+str2"&&vv="+str,true); The things I have tried did not work, I am a little lost... Thanks much!!! Quote Link to comment https://forums.phpfreaks.com/topic/264812-new-to-ajax-question/ Share on other sites More sharing options...
zimminy Posted June 26, 2012 Author Share Posted June 26, 2012 I guess I'll just load that one var with data pieces and explode it in my other php file.. 1_2_5_6... Quote Link to comment https://forums.phpfreaks.com/topic/264812-new-to-ajax-question/#findComment-1357105 Share on other sites More sharing options...
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