Single Line Calendar with Tables

DeadpoolMarv · June 27, 2012

Hello guy,

I am a newbie and I was task to create a code were this needs to be returned.

Tue Wed Thu Fri Sat Sun Mon Tue

ASEAN Reports 1 2 3 4 5 6 7 8 9

Country

Reports

Report1

Report2

I know it's not that hard for you guys that is why I came to this site.

Thanks in advance.

Skewled · June 27, 2012

This will return a print out of that. It's up to you to tweak and add the data you want.

<?php

echo 'ASEAN Reports<br>';
echo '<table>';
echo '<tr>';
echo '<th>Tue</th>';
echo '<th>Wed</th>';
echo '<th>Thur</th>';
echo '<th>Fri</th>';
echo '<th>Sat</th>';
echo '<th>Sun</th>';
echo '<th>Mon</th>';
echo '</tr>';
echo '<tr>';
echo '<td>1</td>';
echo '<td>2</td>';
echo '<td>3</td>';
echo '<td>4</td>';
echo '<td>5</td>';
echo '<td>6</td>';
echo '<td>7</td>';
echo '</tr>';
echo '</table>';
echo '<br>';
echo 'Country<br>';                           
echo 'Reports<br>';                           
echo 'Report1<br>';                           
echo 'Report2<br>';

?>

Drummin · June 27, 2012

Ahh for the fun of it. I'm sure the BIG BOY's could do better but it was fun non the less.

<?php 

if (isset($_POST['month'])){
$m=$_POST['month'];
$y=$_POST['year'];
$viewmonth = "$m-1-$y";
}else{ 
$m = date("n"); 
$y = date("Y");
$viewmonth = date("n-j-Y",strtotime("+0 months"));
}

list($thisMonth,$thisDay,$thisYear) = preg_split('/[\/\-\ \,\.]/', $viewmonth);
$daysinmonth=date("t", mktime(0,0,0,$thisMonth,$thisDay,$thisYear));

?>
    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN"
    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
        <head>
	<title></title>
	<style type="text/css">
	.table{
	background-color:#ddd;
	font-family:arial;
	font-size:12px;
	}
	</style>
	</head>
<body>
<form action="" method="post">
	<select name="month" onchange="this.form.submit()">
	<?php
	$months = array(1=>"January", 2=>"February", 3=>"March", 4=>"April", 5=>"May", 6=>"June", 7=>"July", 8=>"August", 9=>"September", 10=>"October", 11=>"November", 12=>"December");

	foreach ($months as $month =>$shown_month){
		if (isset($_POST['month'])){
			$selected_month=($_POST['month']==$month ? 'selected="selected"':'');
		}else{
			$selected_month=($m==$month ? 'selected="selected"':'');
		}
	echo "<option value=\"$month\" $selected_month>$shown_month</option>";
	}
	?>
	</select>
	<select name="year" onchange="this.form.submit()">
	<?php

	foreach(range($y,1960) as $year){		
		if (isset($_POST['year'])){
			$selected_year=($_POST['year']==$year ? 'selected="selected"':'');
		}else{
			$selected_year=($y==$year ? 'selected="selected"':'');
		}
	echo "<option value=\"$year\" $selected_year>$year</option>";
	}
	?>
	</select> 
</form>
<?php
$i=1;
$ii=1;
echo"<table class=\"table\">\r";
echo "<colgroup style='background-color:#efefef'></colgroup>\r";
while ($ii<($daysinmonth+1)){
	$fd2 = date("D", mktime(0, 0, 0, $thisMonth, $ii, $thisYear));
	if ($fd2 == 'Sat' OR $fd2 == 'Sun'){ 
		echo "<colgroup style='background-color:#C6C7CB'></colgroup>\r";
	}
	else{
		echo "<colgroup style='background-color:#ffffff'></colgroup>\r";
	}
$ii=$ii+1;
}
echo "<tr style=\"font-size:.9em;\">\r<th>ASEAN Reports</th>\r";	
while ($i<($daysinmonth+1)){
$fd = date("D", mktime(0, 0, 0, $thisMonth, $i, $thisYear));
	if ($fd == 'Sat' OR $fd == 'Sun'){
		echo "<th align=\"center\" width=\"25\" style='background-color:#dcdcdc'>$fd<br />$i</th>\r";
	}
	else{
		echo "<th align=\"center\" width=\"25\">$fd<br />$i</th>\r";
	}
$i=$i+1;
}
echo "</tr>\r";

$fakerecords=array('Country','Reports','Report1','Report2');
foreach($fakerecords as $record){ 
	echo "<tr>\r<td align=\"left\">$record</td>\r"; 
	for ($d=1; $d<=$daysinmonth; $d++){
		//DB query could be here for current date and link added to this cell
		echo "<td> </td>\r";
	}
echo "</tr>\r";
}
echo "</table>\r";
?>
</body>
</html>

DeadpoolMarv · June 27, 2012

Thanks good Sir.

What if I need to print out a calendar that looks like this?

For the whole month.

Mon Tue Wed Thu Fri Sat Sun Mon Tue Wed

1 2 3 4 5 6 7 8 9 10

jcbones · June 28, 2012


<?php 
//Set calendar to current time.
$date = strtotime('now'); //see manual for accepted formats.
//This puts the day, month, and year in seperate variables
$day = date('d', $date) ;
$month = date('m', $date) ;
$year = date('Y', $date) ;
//This gets us the month name
$monthName = date('F', $date) ; 
//Here we generate the first day of the month
$first_day = mktime(0,0,0,$month, 1, $year) ;
//Here we find out what day of the week the first day of the month falls on
$day_of_week = date('w', $first_day) ;
//Array to hold the days of the week.
$days_of_week = array('Sun','Mon','Tues','Wed','Thurs','Fri','Sat');
//We then determine how many days are in the current month
$days_in_month = cal_days_in_month(0, $month, $year) ;
//Here we start building the table heads
$calendar = '<table class="calendar">';
//first table row.
$calendar .= '<tr>';
for($i = 0; $i < $days_in_month; $i++,$day_of_week++) {
$day_of_week = ($day_of_week > 6) ? 0 : $day_of_week;
$calendar .= '<td>' . $days_of_week[$day_of_week] . '</td>';
}
$calendar .= '</tr>';
//second table row.
$calendar .= '<tr>';
for($i = 1; $i < ($days_in_month + 1); $i++) {
$calendar .= '<td>' . $i . '</td>';
}
$calendar .= '</tr></table>';


//send the calendar to output.
echo '<body>' . $calendar . '</body>';
?>

Drummin · June 28, 2012

A little update to the TOP of my version.

$y = date("Y");
if (isset($_POST['month'])){
$m=$_POST['month'];
$cy=$_POST['year'];
$viewmonth = "$m-1-$cy";
}else{ 
$m = date("n"); 
$y = date("Y");
$viewmonth = date("n-j-Y",strtotime("+0 months"));
}

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Single Line Calendar with Tables

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