Rotating day assignments with exclusions.

[mrplatts]

Hi,
First, I'm not a programmer, but understand the basics of programming langauges.  I'm learning PHP, so if this seems obvious, I'm sorry in advance. 

What I want to do is allow a user to input a start date & an end date.  The script should then assign a six-day rotation of the numbers 1 thru 6 to weekdays only.  This much I have done.

what I need now is an easy way to:
(1) collect  exceptions to the above rule  -- i.e. weekdays that should not be incremented/assigned a rotation number.

(2) apply those exceptions to the output (eventually exportation to MySQL table, right now, an HTML TABLE.

I'm assigning the rotation using an if - else statement, first checking that the date('w', $s) is not 0 or 6 (weekend) ... I have the rotor working if I manually feed the exclusions, if it passes, it assigns the rotation number, and increments for the next cycle.  Otherwise, it moves on.  THen there is another if{} to check if the number has incremented to seven, then bumps it back to one.

$current_date != $do1 && $current_date != $do2 && $current_date != $do3 && $current_date != $do4

of course, this is terrible in efficient, and not very useful.

Any clues on how you would do this? Ideas to make the code more efficient?

Thanks alot,

Rich

[Barand]

Try something like
[code]
<?php
$excepts = array('2006-12-25', '2006-12-26', '2007-01-01') ;

$today = mktime(0,0,0);
$count = 0;

echo '<pre>';
for ($i=0; $i<90; $i++) {
    $t = strtotime("+$i days", $today);
    $dt = date('Y-m-d', $t);
    if (!in_array($dt, $excepts) && date('w',$t)!=0 && date('w',$t)!=6) {
        $rota = $count++ % 6 + 1;
        if ($rota==1) echo "\n\n";
        printf("<br/>%d : %-5s%-10s", $rota, date('D', $t), date ('d-m-Y', $t) );
    }
}
echo '</pre>';
?>
[/code]

[mrplatts]

Wow, thanks, I implemented some version of this and it worked great.  Thanks a million.

Rich