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Hi All

 

My user name says it all, I have now LostMyMarbles and need help. I am very new to PHP and have been trying to work this out over the last couple of days. I just cannot spot why my sub drop down is not getting populated.

 

Can anyone spot my error... I would be very grateful:

 

 

 

 

<link href="images/favicon.ico" rel="icon" />

<?php require_once('Connections/cnTestingMedia.php'); ?>

 

<form action="" method="post">

<select name="client">

<?php

mysql_select_db($database_cnTestingMedia, $cnTestingMedia);

$client_query = "SELECT clientid, clientname FROM tblclients";

$client_result = mysql_query($client_query);

 

while($client = mysql_fetch_array($client_result)) {

if($_POST['client'] == $client['clientid'] ) {

echo '<option selected value="' . $client['clientid'] . '">' . $client['clientname'] . '</option>';

} else {

echo '<option value="' . $client['clientid'] . '">' . $client['clientname'] . '</option>';

}

}

?>

</select>

<input type="submit" name="submit" value="GO" /><br /><br />

<select name="promotion">

<?php

 

if($_POST['submit']) {

echo $_POST['client'];

mysql_select_db($database_cnTestingMedia, $cnTestingMedia);

$promotion_query = "SELECT promotion_name FROM tblpromotions WHERE clientid = '{$_POST['client']}'";

 

 

while($promotion = mysql_fetch_array($promotion_result)) {

echo '<option value="' . $promotion['promotion_name'] . '">' . $promotion['promotion_name'] . '</option>';

}

}

 

?>

</select>

</form>

 

 

 

The Client list populates perfectly but NOTHING happens for the Promotion list.

 

Thank you.

Link to comment
https://forums.phpfreaks.com/topic/270454-dynamic-cascading-drop-downs/
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I don't know if you made an error when pasting your code here, but you are not executing your second query.

 

$promotion_query = "SELECT promotion_name FROM tblpromotions WHERE clientid = '{$_POST['client']}'";
$promotion_result = mysql_query($promotion_query);

 

I also strongly suggest that you use PDO or MySQLi because the mysql_* extension is getting deprecated. Your code is also vulnerable to SQL injection. Please search Google for more information.

Edited by Andy123
This thread is more than a year old. Please don't revive it unless you have something important to add.

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