How Do I Print Inputted Text With User Choices?

[imstylin1]

$usertxt=$_POST['usertxt'];

$font=$_POST['font'];

$size=$_POST['size'];

$color=$_POST['color'];

 

These are my variables brought over from a page that is below:

 

<form method="post" action="displaytext.php">

<p>What text would you like changed?<input type="text" name="usertxt" />

</p>

<p>Enter your font

<select name="font">

<option value="Verdana">Verdana</option>

<option value="Times New Roman">Times New Roman</option>

<option value="Arial">Arial</option>

<option value="Comic Sans">Comic Sans</option>

</select>

<p>Select your font size<select name="size">

<option value="1">1</option>

<option value="2">2</option>

<option value="3">3</option>

<option value="4">4</option>

</select>

<p>Select the color you would like<select name="color">

<option value="red">Red</option>

<option value="blue">Blue</option>

<option value="green">Green</option>

<option value="yellow">Yellow</option>

</select>

<P><input type="submit" name="Submit" value="Submit" />

 

The variables have the correct data in them, I checked.

How can I show the inputted text in the size, font and color the user chose?

I tried echo command but don't know how to structure. Thanks.

[deoiub]

echo is how you output the contents of a variable. What happened when you tried it?

[imstylin1]

The echo showed the proper contents of the variables. I actually solved this. To set the style of what the user chose, I used:

 

<style type="text/css">

p {color:<?php echo $color; ?>; font:<?php echo $font; ?>; font-size:<?php echo $fontsize; ?>%}

</style>

I went back and changed the 1,2,3,4 for font size to 50, 100, 150, 200

I then used htmlspecialchars to output with css styling:

 

Here is your text:

<p><?php echo htmlspecialchars($usertxt); ?></p>

And it all worked!

I am a newbie, so getting the stuff to do what I want is challenging, but at least there are functions to accomplish it.