Insert Id Number Into Database

[justlukeyou]

Hi,

 

I can echo the id number of a member. "The ID Number is 239." I am now trying to enter number of the user as the organiserid.

 

I can insert eventname into the table but I am struggling to add the id number. Can anyone advise how I should be doing this please.

 

 

<div class="boardintro">
The ID Number is <?php echo (!empty($row['id'])) ? $row['id'] : ''; ?>
</div>

<?php
if(isset($_POST['createevent'])){
 $organiserid = trim($_POST['$id']);
$eventname = mysql_real_escape_string(trim($_POST['eventname']));

{
 $query = mysql_query("INSERT INTO table (eventname, organiserid) VALUES ('" .$eventname."', '" .$organiserid."')");
 if($query) {
 } else {
$error = "There was a problem with the submission. Please try again.";
 }
}
}
?>

[MDCode]

"I am struggling" does not define your problem? What is it doing that it shouldn't, or what is it not doing that is should?

[justlukeyou]

The code does not insert the id from table1 into table2.

 

I can echo the id from table1. I can insert a question into table2 but I cant insert the users ID when they ask a question.

[MDCode]

Have you tried echoing mysql_error() ?

[justlukeyou]

No.

 

I think its this code which is wrong? Ive tried around 10 different variants but cant get any to work. Does this look right?

 

	 $organiserid = trim($_POST['$id']);

[MDCode]

No. I don't believe you can post a variable. Even if you can you have it in single quotes which will not parse it's value

[justlukeyou]

Oh right. Is there a standard way of posting data from one table to another?

[MDCode]

Selecting from it getting the row and assigning it to a variable.

[justlukeyou]

Okay, so Im selecting it from the database and I can echo it. How do I allocate it to a variable.

 

So to transfer a variable from one table to another table I have to allocate it to a variable first?

 

 <?php
$query = "SELECT * FROM users WHERE id = " . intval($_SESSION['userID']) . " LIMIT 1";
if ($result = mysql_query($query)) {

		    $row = mysql_fetch_array($result);
}
		    ?>

[justlukeyou]

Sorry, thought I had it.

[MDCode]

If you are using mysql_fetch_array you can use:

 

$id = $row['name of your column that contains the id'];

[justlukeyou]

Brilliant, thanks.

 

I just need to do this and it worked fine:

 

  $organiserid = $row['id'];