Variables in URL

[VogrothUnmaker]

[quote author=The Little Guy link=topic=114878.msg467647#msg467647 date=1163473977]
Maybe it will work this way
[code]<?php
$comic = $_GET['comicnum'];
switch($comic){
case 1:
    $image = '<img alt="alt text" src="Imagename1.jpg">';
break;
case 2:
    $image = '<img alt="alt text" src="Imagename2.jpg">';
break;
case 3:
    $image = '<img alt="alt text" src="Imagename3.jpg">';
break;
}
echo $image;
?>[/code]
[/quote]
[size=8pt][color=teal]This codes all faulty too... it prints out the code itself replacing the image tag with the images but it shows them all along with the rest of the code.[/color][/size]

[VogrothUnmaker]

This is only a test post I'm having trouble posting something

[VogrothUnmaker]

Code I want in Javascript form lacks variable appended to url:
[code]var imagenum = 5
var finalnum = 5
function wayBack()
{ imagenum=1
drawComic()
}
function nxtback()
{ if(imagenum > 1)
{ imagenum--
drawComic()
}
}
function nxtfwd()
{ if(imagenum < finalnum)
{ imagenum++
drawComic()
}
}

function wayFwd()
{ imagenum = finalnum
drawComic()
}
function drawComic()
{ document.comic.src="comic/"+imagenum+".jpg"
}[/code]
Website code came from view sourcecode: [url=http://69.248.112.19/]http://69.248.112.19/[/url]

[VogrothUnmaker]

I've been reading php books and online tutorials everywhere and none of them are giving me what I need, I know what I'm asking for can be done but I cant find it anywhere? Does anyone have [i]any[/i] ideas?

[The Little Guy]

Two things...

1. Could you Re-explain what is trying to be accomplished
2. Do you have a link to the problem?

[VogrothUnmaker]

Look at this website [url=http://69.248.112.19/]http://69.248.112.19/[/url] I am trying to host a webcomic and I want something like that. My problem is I do not know how to code it in PHP. I need PHP because I want to display the comic number in the url and you can not do that with javascript. I do not know how else to explain it and I cant link you to my website because my server is not connected to the internet (i am having port fowarding issues).

[The Little Guy]

Try this:
[code]<?php
echo'<img alt="Comic '.$_GET['imagenum'].'" src="/comic/'.$_GET['imagenum'].'.jpg">';
?>[/code]

[VogrothUnmaker]

Wouldnt I have to define how many Imagenumbers there are?

[taith]

heres a thought...
[code]
<?
$comic=$_GET['comicnum'];
if(empty($comic)) $comic = date(z);

echo '<img alt="alt text" src="'.$comic.'.jpg">';
?>
[/code]

[VogrothUnmaker]

How would I specify the date? I dont understand.  :'( I have no talent for programming.

[VogrothUnmaker]

I think I found what Im looking for in a website but when I open the source code I cant see any of the php script. I am using firefox, is there a plugin i can use to view php script?

[taith]

the date(z) is from 0-365 (including loop years)
just name your images one of them numbers, and on that day, i'll show...

then you just

[code]
<?
$comic=$_GET['comicnum'];
if(empty($comic)) $comic = date(z);

echo '<img alt="alt text" src="'.$comic.'.jpg">';

$pd=$comic -1;
$nd=$comic +1;
echo '<a href="?comic='.$pd.'">Previous</a> <a href="?comic='.$nd.'">Next</a>';
?>
[/code]

[fert]

[quote author=VogrothUnmaker link=topic=114878.msg469731#msg469731 date=1163793762]
I think I found what Im looking for in a website but when I open the source code I cant see any of the php script. I am using firefox, is there a plugin i can use to view php script?
[/quote]
PHP is server side the only way to view the PHP code would be to download the file with FTP.