Placing A Page In A Function

[devilsvein]

Im basically working on a site in which I want to display a menu bar on every page. As this site will be built with many pages i feel it would be easier to simply create a function with the menu bar inside it. I have a few questions which i would appreciate if someone could answer.

 

<ul>

<li><a href="#">Home</a></li>
       <li><a href="#">about</a></li>
</ul>

 

Let say I have this code above. would i simply be able to do:

 

function menu ()
{

<li><a href=#>Home</a></li>
       <li><a href=#>about</a></li>
</ul>
}

 

and call the function on specific areas on the page i want it to be displayed. after requiring that file name.

 

Also curious on if i can do if statements inside that function that display certain menu links depending on the outcome of the condition

 

Thanks

[PaulRyan]

Try something like this:

<?PHP

//### Function to display menu
function displayMenu($menu='') {
//### Check to see which menu to show using is else
if($menu == 'home') {
 $menuHTML = '<ul>
	    <li><a href="#">Home Link</a></li>
        <li><a href="#">Home Link</a></li>
        </ul>';

} else if($menu == 'profile') {
 $menuHTML = '<ul>
	    <li><a href="#">Profile Link</a></li>
	    <li><a href="#">Profile Link</a></li>
        </ul>';

} else {
 $menuHTML = '<ul>
	    <li><a href="#">Default Link</a></li>
	    <li><a href="#">Default Link</a></li>
        </ul>';
}

//### Return select menu
return $menuHTML;
}

//### Displays default links
echo displayMenu();

//### Displays home links
echo displayMenu('home');

//### Displays profile links
echo displayMenu('profile');

?>

Edited December 29, 2012 by PaulRyan