phpjayx Posted February 3, 2013 Share Posted February 3, 2013 The below function is when I have my users log on. I've been working on this for hours, still unable to figure it out.... When I login with a valid user ID, it correctly logs in... My problem is getting the Alerts to work. When my data did not have mulitple return values it worked... but now that I added the additional parameter from the PHP file, the alerts do no work anymore.... I've attempted to use a $.parseJSON statement on the returnValue, but that doesn't work.....I don't know how to get at the "false" or "-1" output Any suggestions???? Please -------------------------------------------------the return statement from my PHP file return $json.'^'.$json1; -------------------my debugger output when entering an invalid password ^false --------------------------------------------------------- My .js file function onSuccessLogin(data) { var temp = data.split("^"); var returnValue = temp[1]; var returnValue2 = temp[2]; parseDataJson(returnValue2); if (returnValue == 'false') alert('Login fail'); else { if (returnValue == '-1') { alert('You need to click on your email confirmation first'); } else {.......................... Link to comment https://forums.phpfreaks.com/topic/273971-using-returnvalues-with-an-array-problems/ Share on other sites More sharing options...
phpjayx Posted February 3, 2013 Author Share Posted February 3, 2013 Ignore... I figured it out..... Almost the same code.... I didn't realize it was stopping on the error within the function parseDataJson(returnValue2); So I just had to move that line down in the else statement........... Link to comment https://forums.phpfreaks.com/topic/273971-using-returnvalues-with-an-array-problems/#findComment-1409823 Share on other sites More sharing options...
Recommended Posts
Archived
This topic is now archived and is closed to further replies.