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I am running a mysql query with the code below but i cannot get the results from multiple rows in a table.

I echo the results and all i get is Array. Help will be appreciated. Thank you

 

The $row should echo all the fields under code1 in the table.

 

Thank you

mysql_connect('localhost', 'u', 'C');
mysql_select_db('u');
//
$result = mysql_query("SELECT code1 FROM codes")
or die(mysql_error());
$row = mysql_fetch_assoc($result);
echo ("<center> <font color=#FF0000 face=Verdana size=2><b>$row</b></font>");

the reason for the echo statement was to see exactly what the problem was. This is what i want done

To receive a variable from a form and test it against all the rows in a database column and if it finds one that corresponds to that row, then go to another page

The code is below

 

$code1=$_POST['code'];
mysql_connect('localhost', 'u', 'C');
mysql_select_db('u);
//
$result = mysql_query("SELECT code1 FROM codes")
or die(mysql_error());
$row = mysql_num_rows($result);

//
if ($row[0] =='$code1') {
include ("mynewpage.php");
   } else {
   echo ("<center> <font color=#FF0000 face=Verdana size=2><b>Invalid Code!</b></font>");
   include("oldpage.php"); } 

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