Referencing rows

newhip · February 22, 2013

Ok im a super newb and i dont know how to to reference the data in my mysql table. I wrote a code that uploads a file to a server then to a database where its echoed out afterwards. The code also echoes out the id in the table's field so i know the id but i dont know how to afterwards reference it in the url. It's prob really basic but i can't figure it out. Can someone help me out or hint. Would be very appreciated. Here's the code

<?php
$conn=mysql_connect("localhost","root","");
$select=mysql_select_db("project",$conn);
$title=$_POST['title'];
$pic=$_FILES['pic']['tmp_name'];
$pic2=$_FILES['pic']['name'];
$desc=$_POST['desc'];
$path="upload/".$pic2;
$themove=move_uploaded_file($pic,$path);
$sqlqry=mysql_query("INSERT INTO media(title,pic,desct) VALUES ('$title','$path','$desc')");
echo $hmmm=mysql_insert_id($conn);
$searr="SELECT * FROM media WHERE id='$hmmm'";
$seartt=mysql_query($searr);
$burp=mysql_fetch_array($seartt);
?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>New Uploaded Page</title>
</head>


<body>
<a href="#"><h1><?php  echo $burp['title'];  ?></h1></a><br /><br />
<img src="<?php
  echo $burp['pic'];

?>" /><br /><p><br /><?php
echo $burp['desct'];
?></p>
</body>
</html>

Barand · February 22, 2013

If you have just inserted the record using VALUES ('$title','$path','$desc') why do you then query the table to get the values for title and desct?

newhip · February 22, 2013

To echo it later on in the page. Is that bad practice?

waynew · February 22, 2013

Change

<a href="#"><h1><?php echo $burp['title']; ?></h1></a>

to

<h1><a href="blurb.php?id=<?php echo $hmmm; ?>"><?php echo $burp['title']; ?></a></h1>

Note that you'll have to create a page called blurb.php

Edited February 22, 2013 by waynewex

Barand · February 22, 2013

It's an inefficient use of resources when you already have the values you want in $title and $desc. You would only need to do that on another page

newhip · February 22, 2013

what does the blurp.php page do? or is it just an example of something i could be linking to?

waynew · February 22, 2013

Barand is right:

<?php
$conn = mysql_connect("localhost", "root", "");
$select = mysql_select_db("project", $conn);


$title = mysql_real_escape_string($_POST['title'], $conn);
$pic = $_FILES['pic']['tmp_name'];
$pic2 = $_FILES['pic']['name'];
$desc = mysql_real_escape_string($_POST['desc'], $conn);
$path = mysql_real_escape_string("upload/".$pic2, $conn);


$themove = move_uploaded_file($pic,$path);


$sqlqry = mysql_query("INSERT INTO media(title,pic,desct) VALUES ('$title','$path','$desc')", $conn);
$id = mysql_insert_id($conn);

?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>New Uploaded Page</title>
</head>

<body>
   <h1>
       <a href="blurb.php?id=<?php echo $id; ?>">
           <?php echo htmlentities($title, ENT_QUOTES, "utf-8"); ?>
       </a>
   </h1>
   <br />
   <br />
   <img src="<?php echo htmlentities($path, ENT_QUOTES, "utf-8"); ?>" /><br />
   <p>
       <br />
       <?php echo htmlentities($desc, ENT_QUOTES, "utf-8"); ?>
   </p>
</body>
</html>

One less query...

Edited February 22, 2013 by waynewex

waynew · February 22, 2013

what does the blurp.php page do? or is it just an example of something i could be linking to?

Just an example page you could link to.

newhip · February 22, 2013

Barand are you saying i should not input it in the table because im echoing it on the same page? I get that i can just echo it out on here because i grabbed the data from the form. Is that what you mean?

waynew · February 22, 2013

Barand are you saying i should not input it in the table because im echoing it on the same page? I get that i can just echo it out on here because i grabbed the data from the form. Is that what you mean?

He's saying that you don't need to run the SELECT query because the data you're inserting is available to the rest of your script. Although one could argue that you should be using the Post/Redirect/Get pattern: http://en.wikipedia.org/wiki/Post/Redirect/Get

newhip · February 22, 2013

Barand is right:

<?php
$conn = mysql_connect("localhost", "root", "");
$select = mysql_select_db("project", $conn);


$title = mysql_real_escape_string($_POST['title'], $conn);
$pic = $_FILES['pic']['tmp_name'];
$pic2 = $_FILES['pic']['name'];
$desc = mysql_real_escape_string($_POST['desc'], $conn);
$path = mysql_real_escape_string("upload/".$pic2, $conn);


$themove = move_uploaded_file($pic,$path);


$sqlqry = mysql_query("INSERT INTO media(title,pic,desct) VALUES ('$title','$path','$desc')", $conn);
$id = mysql_insert_id($conn);

?>
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>New Uploaded Page</title>
</head>

<body>
<h1>
<a href="blurb.php?id=<?php echo $id; ?>">
<?php echo htmlentities($title, ENT_QUOTES, "utf-8"); ?>
</a>
</h1>
<br />
<br />
<img src="<?php echo htmlentities($path, ENT_QUOTES, "utf-8"); ?>" /><br />
<p>
<br />
<?php echo htmlentities($desc, ENT_QUOTES, "utf-8"); ?>
</p>
</body>
</html>

One less query...

Oh ok I think i get it. I didnt know you could do that. But like now how do i go access that page in the url with that info displayed? Like in a www.example.com/upload.php? manner?

Barand · February 22, 2013

this is where you need the SELECT query

blurb.php

<?php

if (isset($_GET['id'])) {
$id = intval($_GET['id'];
$sql = "SELECT title, path, desct
 FROM media
 WHERE id = $id";

$result = mysql_query($sql);

// process results
}

Edited February 22, 2013 by Barand

newhip · February 22, 2013

I'm kinda really confused now what is the blurb.php file now? is it because i shouldnt be displaying on the page that process's the upload? I still dont understand how to reference the page in the url

Barand · February 22, 2013

is it because i shouldnt be displaying on the page that process's the upload?

There is no reason why you shouldn't display in the page that does the upload. What I am saying is that it is a waste of time doing a SELECT query to get the data you have just uploaded because you already have that data :facewall:

Edited February 22, 2013 by Barand

newhip · February 22, 2013

this is where you need the SELECT query

blurb.php

<?php

if (isset($_GET['id'])) {
$id = intval($_GET['id'];
$sql = "SELECT title, path, desct
 FROM media
 WHERE id = $id";

$result = mysql_query($sql);

// process results
}

Ok... but what does that have to do with the blurb.php ?

Barand · February 22, 2013

I still dont understand how to reference the page in the url

<a href="blurb.php?id=<?php echo $id; ?>">

where "blurb.php" is whatever page you want to link to and the id is passed in the query string (eg ?id=123)

newhip · February 22, 2013

Ok sry Barand I'm still a little confused please bare with me :facewall: ...

Are you saying that i would need to create a new page that is linked to upload.php to be able to refenrence the data in the table?

Barand · February 22, 2013

No No No

I am saying you can, not need

The code also echoes out the id in the table's field so i know the id but i dont know how to afterwards reference it in the url.

We are attempting to answer that question for you.

newhip · February 22, 2013

oh ok but if the id is 123 i should be able the access the populated page under www.example.com/upload.php?id=123 ?

Barand · February 22, 2013

How can it when you don't know the id until after the upload?

newhip · February 23, 2013

No i mean if i upload and then want to reference it later or something older in the database

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Referencing rows

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