elim Posted March 20, 2013 Share Posted March 20, 2013 (edited) first of all I'm using this site as a template for what I'm trying to do except im adding a search box on top www.dougv.com/demo/jquery_sort_records/js.php (for some reason link doesnt work so copy and paste into browser) I want to create a simple search box that will search upon a certain attribute and display any results found (basically a filter). Here's what I have so far as part of the code. so far the table appears perfectly however I want to add a search box that will search upon the first name attribute. any help? <script type="text/javascript" src="jquery-1.3.1.min.js"></script> <script type="text/javascript" src="jquery.tablesorter.min.js"></script> <script type="text/javascript"> $(document).ready(function() { $("#sortedtable").tablesorter({ sortlist: [0,0] }); }); </script> </head> <body> <?php if(!$link = mysql_connect("database_server", "user_name", "password")) { echo "Cannot connect to db server"; } elseif(!mysql_select_db("database_name")) { echo "Cannot select database"; } else { if(!$rs = mysql_query("SELECT * FROM table")) { echo "Cannot parse query"; } elseif(mysql_num_rows($rs) == 0) { echo "No records found"; } else { echo "<table id=\"sortedtable\" class=\"bordered\" cellspacing=\"0\">\n"; echo "<thead>\n<tr>"; echo "<th>Record ID</th>"; echo "<th>First Name</th>"; echo "<th>Last Name</th>"; echo "<th>Birthday</th>"; echo "<th>Department</th>"; echo "</tr>\n</thead>\n"; while($row = mysql_fetch_array($rs)) { echo "<tr><td>$row[person_id]</td><td>$row[person_name]</td><td>$row[person_surname]</td><td>$row[person_birthdate]</td><td>$row[person_department]</td></tr>\n"; } echo "</table><br />\n"; } } ?> <form name="search_form" method="POST" action="js.php"> <font face="Calibri"> </font> Search: <input type="text" name="search_b" value="" /> <input type="submit" name="search" value="Search for your term..."> </input> </form> Edited March 20, 2013 by elim Quote Link to comment Share on other sites More sharing options...
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