tpatterson1 Posted November 17, 2006 Share Posted November 17, 2006 I know this is probably really simple, but I can't figure it out.I'm trying to select information from my database and display certain information based on the queryFor example:[code]$bareQuery = "select * from XXXXX ";$queryall = $bareQuery.$sorted;$resultall = MYSQL_QUERY($queryall);$numberall = mysql_Numrows($resultall);if ($numberall==0) { echo "No Records Found !";}else if ($numberall>1)[/code]And then that would list whateverBut I want to display items when a certain number is reached.I guess it's kind of hard to explain.I'm going to have the numbers 1-5 in a database field.If the field has a number 1 in it, i want it to pull certain information, if it has a number 2, different information, and etc.I hope this makes sense.Can someone please help me? Link to comment https://forums.phpfreaks.com/topic/27616-simple-question/ Share on other sites More sharing options...
taith Posted November 17, 2006 Share Posted November 17, 2006 i think you're looking for something like this...[code]$result = mysql_query("select * from XXXXX ");if(mysql_num_rows($result)==0){ echo "No Records Found !";}else{ while($row = mysql_fetch_array($result)){ echo $row['name']. " - ". $row['age']; }}[/code] Link to comment https://forums.phpfreaks.com/topic/27616-simple-question/#findComment-126295 Share on other sites More sharing options...
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