tpatterson1 Posted November 17, 2006 Share Posted November 17, 2006 I know this is probably really simple, but I can't figure it out.I'm trying to select information from my database and display certain information based on the queryFor example:[code]$bareQuery = "select * from XXXXX ";$queryall = $bareQuery.$sorted;$resultall = MYSQL_QUERY($queryall);$numberall = mysql_Numrows($resultall);if ($numberall==0) { echo "No Records Found !";}else if ($numberall>1)[/code]And then that would list whateverBut I want to display items when a certain number is reached.I guess it's kind of hard to explain.I'm going to have the numbers 1-5 in a database field.If the field has a number 1 in it, i want it to pull certain information, if it has a number 2, different information, and etc.I hope this makes sense.Can someone please help me? Quote Link to comment Share on other sites More sharing options...
taith Posted November 17, 2006 Share Posted November 17, 2006 i think you're looking for something like this...[code]$result = mysql_query("select * from XXXXX ");if(mysql_num_rows($result)==0){ echo "No Records Found !";}else{ while($row = mysql_fetch_array($result)){ echo $row['name']. " - ". $row['age']; }}[/code] Quote Link to comment Share on other sites More sharing options...
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