edwardda Posted April 12, 2013 Share Posted April 12, 2013 <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"><html xmlns="http://www.w3.org/1999/xhtml"><head><meta http-equiv="Content-Type" content="text/html; charset=utf-8" /><title>newland</title></head> <body><p>thank you,<?php echo $_POST['firstName']; ?>,for filling out my form </p></body></html Quote Link to comment Share on other sites More sharing options...
Barand Posted April 13, 2013 Share Posted April 13, 2013 So.... Quote Link to comment Share on other sites More sharing options...
Solution Barand Posted April 13, 2013 Solution Share Posted April 13, 2013 (edited) Why a new topic for this post? If this (from your other post) is the form you are processing <form id="frm_name" name="frm_name" method="post" action="test_form_processor.php"> <label for="textfield">First Name</label> <input type="text" name="textfield" id="textfield" /> <input type="submit" name="button" id="button" value="Submit" /> </form> then you can see that the input field name is "textfield" You are trying to process it as $_POST['firstName']. Try $_POST['textfield'] Edited April 13, 2013 by Barand Quote Link to comment Share on other sites More sharing options...
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