unique visits per 24hr

[subhomoy]

Hiii every one i'm trying to count the impression of the specific image once in 24hr.

 

here is the code

<?php
require_once '../dbconfig.php';
$mid = $_REQUEST['id'];      <-------------------------   Image Id
 $ip = $_SERVER['HTTP_HOST'];<------------------------- Viewers ip
 $date = date("Y-m-d");<-------------------------  current date
$qh = mysql_query("SELECT date,ip FROM image_hits WHERE image_id='$mid'") or die(mysql_error()); <------------------------- It will check whether any rows using that image id is present or not... if not it will produce "0"
 while($a = mysql_fetch_array($qh)){
     $date1 = $a['date'];
     $ip1 = $a['ip'];
 }
 if(($ip==$ip1) && ($date==$date1)){<------------------------- Checking current date with the database values
     $h = mysql_query("SELECT visits FROM image_hits WHERE image_id='$mid'") or die(mysql_error());
     while($b = mysql_fetch_array($h)){
         $visits = $b['visits'];
     }
     echo $visits;
     }
 else {    <----------------------- it will select the current values and will increment it by 1 and ten insert into database...
    $qh1 = mysql_query("SELECT visits FROM image_hits") or die(mysql_error());
    while($c = mysql_fetch_array($qh1)){
    $visits1 = $c['visits']; 
    }
    $visits2 = $visits1+1;
   $hits = mysql_query("UPDATE image_hits SET visits='$visits2' WHERE date='$date' AND ip='$ip'") or die(mysql_error());      
   while($d = mysql_fetch_array($hits)){<-------------------------the error shows...    
       $visits = $d['visits'];
   }
   echo $visits1;
   }
?>

The warning message is hsown below

 

Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\Mobitalk.com\members\image_hits.php on line 25

 

Any help will greatly appreciated....

 

If there is any easier way to do then plz recommend...

 

Thank You....

 

[seandisanti]

Your issue is because you're using inline variables improperly.  you're looking for records that have a date value of '$date' rather than the value contained therein. if you want to see what i mean, just add this in place of line 23

die("UPDATE image_hits SET visits='$visits2' WHERE date='$date' AND ip='$ip'");

That's the string you're passing to mysql

***edit*** also, you should be checking mysql_affected_rows() to get the number affected for an update, rather than fetching results.

[Barand]

So this is what you are trying to do?

 

 

 

else {    <----------------------- it will select the current values and will increment it by 1 and ten insert into database...
    $qh1 = mysql_query("SELECT visits FROM image_hits") or die(mysql_error());
    while($c = mysql_fetch_array($qh1)){
    $visits1 = $c['visits'];
    }
    $visits2 = $visits1+1;

Loop through all records in image_hits table, get the number of visits from the last record then increment it.

Then

 

$hits = mysql_query("UPDATE image_hits SET visits='$visits2' WHERE date='$date' AND ip='$ip'") or die(mysql_error());

Update all the images visited by that IP today and give them all the same number of visits