Parse error: syntax error

[guybrown]

Hi all

 

I'm new to programming and this forum and know very little about php. Any help would be greatly appreciated and I look forward to contributing and supporting others as my knowledge increases.

 

I am trying to get a 'counter' php file working on my localhost. When I run the php file in chrome I get the following error:

 

Parse error: syntax error, unexpected '$result' (T_VARIABLE), expecting ',' or ';' in C:\xampp\htdocs\database\counter.php on line 8

 

My php file contains the following:

 

 

<?php

require($_SERVER["DOCUMENT_ROOT"]."/database/config/db_config.php");

$connection = @mysql_connect($db_host,$db_user, $db_password) or die("error connecting");

mysql_select_db($db_name, $connection);

 

$query = "SELECT * FROM counter";

echo $query

$result = mysql_query($query, $connection) or die(mysql_error());

echo $result

$views = mysql_result($result, 0, "num_views");

echo $views

 

$views++;

 

$query = "UPDATE counter SET num_views = $views";

mysql_query($query, $connection) or die(mysql_error());

 

echo "This page has been viewed ".$views." times.";

?>

 

I created the counter table in phpmyadmin and it has the following details:

 

 

# Name Type Collation Attributes Null Default Extra Action 1 num_views int(5)   UNSIGNED No 0    Change  Drop  Browse distinct values

 

Any help appreciated.

 

Regards,

 

Guy Brown

counter.php

[PravinS]

Add semicolon( on lines

 

echo $query

echo $result

echo $views

[guybrown]

Add semicolon( on lines

 

echo $query

echo $result

echo $views

 

Much appreciated pbs! Thank you very much. The echoes that were there to help me identify any issues were causing the issues. Cheers, Guy.