Undefined index: pages.BGimageID and bgimages.BGimageID

[jarv]

$sql2 = "SELECT * FROM pages INNER JOIN bgimages ON pages.BGimageID=bgimages.BGimageID";

$result2 = mysql_query($sql2);

<?php while($row2 = mysql_fetch_array($result2))

										{

										if($row2['pages.BGimageID'] == $row2['bgimages.BGimageID']){

											echo '<input type="radio" name="BGimageID" value="'.$row2['BGimageID'].'" checked /><img src="../images/'.$row2['BGimage'].'" width="150" />';

											} else {

											echo '<input type="radio" name="BGimageID" value="'.$row2['BGimageID'].'" /><img src="../images/'.$row2['BGimage'].'" width="150" />';

											}

										}

									?>

 

[dannon]

There are no pages.BGimageID and bgimages.BGimageID keys in your $row2 array.

You need to use mysql_fetch_assoc, instead of mysql_fetch_array.

[jarv]

thanks, I just changed that and still get the same error?!

[dannon]

Do print_r($row2) to check what you are receiving from the query. I don't think you need the 'pages.' and 'bgimages.' here: if($row2['pages.BGimageID'] == $row2['bgimages.BGimageID']){

 

 

[jarv]

print_r($row2)  outputs an array of what is in the database

 

 

I think the problem lies where I am trying to join the 2 tables

 

I just want to check if BGimageID in Pages table is the same as BGimageID is the same as the one in bgimages table and if it is then CHECK the radio button

[dannon]

Are pages.BGimageID and bgimages.BGimageID in your $row2 array? If not then you might not be joining the tables correctly.

[jarv]

no, they are not there

[jarv]

can anyone help me with the sql please?