PHP Drop Down menu will not show array value?

[Dicko_md]

$array = array("3", "6", "12", "18", "24");

$opt = '';
	for ($i=0; $i<sizeof($array); $i++) $opt .= "<option value='$array[i]'> $array[i] </option>";
	$html = "
		<form method='get' action='index.php?s=upgrade'>
		<input type='hidden' name='s' value='upgrade' />
		<input type='hidden' name='memid' value='$_GET[memid]' />
		<span class='formlabel'>Months:</span> <select name='nummonths'>$opt</select> 
<input type='submit' class='button' value=' Submit ' name='gopay'>
		<br /><br />
		</form>
	";

The above code should show 3, 6, 12, 18, 24 in a drop down menu but it is only showing 5 blank spaces.

 

Can anyone spot what I have done wrong ? If I put anyMonths in the $array between the options like below theMonths shows up on all 5 lines of the drop down

$opt .= "<option value='$array[i]'> $array[i] Months </option>";

Thanks 

 

Martyn

[davidannis]

try putting the variable in curly braces

{$array[i]}

from the php echo page examples:

 

// You can also use arrays
$baz = array("value" => "foo");

echo "this is {$baz['value']} !"; // this is foo !

Edited June 10, 2013 by davidannis

[mac_gyver]

your loop variable is $i

 

you are just using the letter i in your code and that's not the php variable $i

[Dicko_md]

Hi mac_gyver

  Thanks for that. I think I looked at it took long and missed the obvious.

 

It works a treat now.