latemodern Posted November 4, 2005 Share Posted November 4, 2005 Hi There, I am trying to construct a MYSQL query to filter out people who are too old or too young based on their date of birth and the users $maxage and $minage specifications I created an equation that takes that date if birth (from the users.dob category) and calculates their age and aliases it as 'age'. In my WHERE clause I am trying to get it to only include users whose age is higher than the $minage variable and lower than the $maxge variable. However, mysql returns an error saying that 'age' is an unknown category. Any ideas? Here is the code: //cut out people who are too young $filter = $filter. ' age >=' .$own_minage. ' AND '; //cut out people who are too old $filter = $filter. ' age <=' .$own_maxage. ' AND '; $user_record_query = "SELECT users.user_id, CONCAT(first_name, ' ', last_name) AS name, (YEAR(CURDATE())-YEAR(dob)) - (RIGHT(CURDATE(),5)<RIGHT(dob,5)) AS age, gender.gender, minbeds, maxbeds, minrent, maxrent, minage, maxage, email, phone, personal_description, gendermix.gendermix, file_name, smoker.smoker, studentmix.studentmix, smoking_mix.smokingmix, student.student FROM users JOIN gender ON users.gender = gender.gender_id JOIN uploads ON uploads.user_id= users.user_id JOIN smoker ON users.smoker=smoker_id JOIN studentmix ON users.studentmix_id=studentmix.studentmix_id JOIN smoking_mix ON users.smokingmix_id=smoking_mix.smokingmix_id JOIN users_area_assoc ON users_area_assoc.user_id = users.user_id JOIN area ON area.area_id=users_area_assoc.area_id JOIN student ON users.occupation=student.student_id JOIN gendermix ON users.gendermix_id=gendermix.gendermix_id WHERE $filter" Thanks Chris Quote Link to comment Share on other sites More sharing options...
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