How to create an add button to add all details at once to mysql table

[hance2105]

hello guys, i have the below code which echoes records from tblproduct. a field is displayed with an add button against each retrieved record. how can i have only one add button to add all records at once to the table?

 

<?php session_start(); include('db_connect.php'); $sql = mysql_query("select * from tblproduct"); $num = mysql_num_rows($sql); if($num>0){ echo "<center><table bgcolor='grey' width='80%' border=0>"; echo "<tr bgcolor='#CCCCCC'>";echo "<td><b><center>Product</td>";echo "<td><b><center>Name</td>";echo "<td><b><center>Brand</td>";echo "<td><b><center>Price</td>";echo "</tr>"; while($row = mysql_fetch_assoc($sql)){     extract($row);       echo "<tr>";     echo '<td style="text-align:center;"><img height="100" width="100" src="Images/Products/'.$row['prod_photo'].'"/></td>';      echo "<td style='text-align: center;'>".$row['prod_name']."</td>";      echo "<td style='text-align: center;'>".$row['prod_brand']."</td>";      echo "<td>"."<form name=\"price\" method=\"post\" action=\"ret_addprod.php\">".        "<input type=\"hidden\" name=\"prod_id\" value=".$row['prod_id']." />".        "<input type=\"text\" name=\"prod_price\" />".        "<input type=\"submit\" value=\"Add\" /></form>"."</td>";    }echo "</table>";echo "<center><a href ='retailer_home.php' >Home</a>";} else{    echo "No products found.";} ?>

[chriscloyd]

You are making this much more difficult than needs to be...  But you cant if you are going to have a form on each page.  A way I would do it is after you enter in a price have javascript update that one .  But everyone has their own ways of doing things.

 

From the html5 working draft:

4.10.3 The form element

Content model:

Flow content, but with no form element descendants.

[jcbones]

First you would build your form different, using arrays:

<?php
session_start();
include('db_connect.php');
$sql = mysql_query("select * from tblproduct");
$num = mysql_num_rows($sql);
if($num>0) {
    echo "<form name=\"price\" method=\"post\" action=\"ret_addprod.php\">"
                ."<center><table bgcolor='grey' width='80%' border=0>"
                . "<tr bgcolor='#CCCCCC'>"
                . "<td><b><center>Product</td>"
                . "<td><b><center>Name</td>"
                . "<td><b><center>Brand</td>"
                . "<td><b><center>Price</td>"
                . "</tr>";
    while($row = mysql_fetch_assoc($sql)){
        
            echo "<tr>"
                    .'<td style="text-align:center;"><img height="100" width="100" src="Images/Products/'.$row['prod_photo'].'"/></td>'
                    . "<td style='text-align: center;'>".$row['prod_name']."</td>"
                    . "<td style='text-align: center;'>".$row['prod_brand']."</td>"
                    . "<td>"
                    ."<input type=\"hidden\" name=\"prod_id[]\" value=".$row['prod_id']." />"
                    ."<input type=\"text\" name=\"prod_price[]\" />"
                    ."</td>";
}
echo "</table>"."<input type=\"submit\" value=\"Add\" /></form>"
        ."<center><a href ='retailer_home.php' >Home</a>";
}
else{
    echo "No products found.";
}
?>

Then on:

ret_addprod.php

You would have a processing portion like:

<?php
include('db_connect.php');
if($_SERVER['REQUEST_METHOD'] == 'POST') {
 foreach($_POST['prod_id'] as $index => $id) {
  $sql = sprintf("UPDATE tblproduct SET prod_price = %f WHERE prod_id = %d",
                         $_POST['prod_price'][$index],
                         $id);
 if(mysql_query($sql)) continue;
 exit('There was an error in your syntax<br />' . mysql_error());
 }
}
?>

I don't really like running queries in loops.  The only way to make it work without looping the queries, would require a huge case statement.  If there is a problem with overhead (shouldn't be, unless your server is remote from the db server) perhaps we could write that out.

 

Edit:  I'm an idiot, mixed the syntax for sprintf and mysqli->prepare