jcg31 Posted July 7, 2013 Share Posted July 7, 2013 I am getting an "Unable to jump to row 155 on MySQL result index 4 in C:\wamp\www\Inventory.php on line 64" . This code is just test code to try and isolate this " unable to jump" issue that I am having with a bigger project In the test code I first tried iterating through the recordset (see code below) which worked without issue, providing the output I would have expected and wanted (including category_id 155). The category_id is what I am incrementing, so the test verified that the proper id was being passed and that the proper category_label and category_id was being returned. I then tried accessing the category_label using <?php echo mysql_result($Recordset1, 155, 2); ?> (line 64 in the code) And it threw the error. Any help would be appreciated. Thanks, Jim mysql_select_db($database_Inventoryserver, $Inventoryserver); $query_Recordset1 = "SELECT * FROM category"; $Recordset1 = mysql_query($query_Recordset1, $Inventoryserver) or die(mysql_error()); $row_Recordset1 = mysql_fetch_assoc($Recordset1); $totalRows_Recordset1 = mysql_num_rows($Recordset1); mysql_select_db($database_Inventoryserver, $Inventoryserver); $query_Recordset2 = "SELECT * FROM tasks "; $Recordset2 = mysql_query($query_Recordset2, $Inventoryserver) or die(mysql_error()); $row_Recordset2 = mysql_fetch_assoc($Recordset2); $totalRows_Recordset2 = mysql_num_rows($Recordset2); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Welcome</title> </head> </head> <body> <?php echo mysql_result($Recordset1, 155, 2); ?> <table width="900" border="1"> <?php $i=0; do { ?> <tr> <td><?php echo $row_Recordset1['category_label']; ?></td> <td><?php echo mysql_result($Recordset1, $i, 2); ?></td> <td><?php echo $row_Recordset1['category_id']; ?></td> </tr> <?php $i++ ?> <?php } while ($row_Recordset1 = mysql_fetch_assoc($Recordset1)); ?> </table> </body> </html> <?php mysql_free_result($Recordset1); mysql_free_result($Recordset2); ?> Quote Link to comment https://forums.phpfreaks.com/topic/279938-unable-to-jump-error/ Share on other sites More sharing options...
mac_gyver Posted July 7, 2013 Share Posted July 7, 2013 you should not be trying to access a specific row number in a result set, because it might not exist (your current error, rows start at zero) and there's no guarantee that any row number will always be the data you expect (deleting rows from a table and not using any ORDER BY in your query will result in different data being in any row number in a result set.) your database loop code, wherever you learned it, is inefficient for three reasons - 1) mysql_result() is the slowest way of accessing data because it performs a dataseek followed by a read operation, 2) you are already fetching the row into a variable, using mysql_result() on top of that isn't necessary. just use the fetched data. 3) using a do/while loop takes more code because you must pre-fetch the first row from the result set and you must also add more logic to test if there are any rows at all to avoid errors when accessing non-existent data. you need to (always) use a while(){} loop to iterate over multiple rows from a query - $query = " your query statement here ..."; $result = mysql_query($query); while($row = mysql_fetch_assoc($result)){ code that uses the fetched data in $row .. } i can guarantee that this method won't ever attempt to access rows that don't exist in the result set. it will loop over only the rows that do exist, even if there are zero rows in the result set (in which case it will skip over the loop.) Quote Link to comment https://forums.phpfreaks.com/topic/279938-unable-to-jump-error/#findComment-1439790 Share on other sites More sharing options...
mac_gyver Posted July 7, 2013 Share Posted July 7, 2013 as a continuation of the above replay, there's another (good) reason to NOT use mysql_result() at all. the mysql_ database library is depreciated in php5.5 and should no longer be used and there's no equivalent for the mysql_result() statement in the the mysqli or PDO database libraries that are the replacement for the mysql_ library. Quote Link to comment https://forums.phpfreaks.com/topic/279938-unable-to-jump-error/#findComment-1439793 Share on other sites More sharing options...
jcg31 Posted July 7, 2013 Author Share Posted July 7, 2013 Thanks Mac_gyver. Learned (learning) from forums like this one, bunches of views on how to do things, I apparantly picked the wrong one. My iterating through the recordset was just for the purpose of testing my real need (but good to get your input on that). My real question is how to retrieve a particular row in the recordset? Got my current approach from http://stackoverflow.com/questions/6782615/display-specific-line-or-record-of-a-recordset. So, if Recordset1= Book1 Author1 Cost1 Remainder1 Book2 Author2 Cost2 Remainder2 Book3 Author3 Cost3 Remainder3 Book4 Author4 Cost4 Remainder4 What is the best way to retreive Cost3? Thanks, Jim Quote Link to comment https://forums.phpfreaks.com/topic/279938-unable-to-jump-error/#findComment-1439794 Share on other sites More sharing options...
mac_gyver Posted July 7, 2013 Share Posted July 7, 2013 i had actually typed a line, but removed it before posting the reply above - if you are trying to retrieve a specific row from a database table, you would retrieve that row using its id or using some other identifying means. how do you know you want to retrieve the row that has the Cost3 value in it? what input does your code have that determines what row and what column you want to find? Quote Link to comment https://forums.phpfreaks.com/topic/279938-unable-to-jump-error/#findComment-1439795 Share on other sites More sharing options...
thara Posted July 7, 2013 Share Posted July 7, 2013 Recordset1- as in a result handle from a database call? Or just some array? Quote Link to comment https://forums.phpfreaks.com/topic/279938-unable-to-jump-error/#findComment-1439796 Share on other sites More sharing options...
jcg31 Posted July 7, 2013 Author Share Posted July 7, 2013 Recordset1- as in a result handle from a database call? Or just some array? Recordset1 as from a database call. Quote Link to comment https://forums.phpfreaks.com/topic/279938-unable-to-jump-error/#findComment-1439798 Share on other sites More sharing options...
jcg31 Posted July 7, 2013 Author Share Posted July 7, 2013 (edited) i had actually typed a line, but removed it before posting the reply above - if you are trying to retrieve a specific row from a database table, you would retrieve that row using its id or using some other identifying means. how do you know you want to retrieve the row that has the Cost3 value in it? what input does your code have that determines what row and what column you want to find? Recordset2 comes from the tasks table that contains tasks associated with a particular category of books and marketing of same. Recordset1 has the details of each category. Both tables have category_id as a field. The application takes the contents of Recordset2 and presents the tasks contained within in table form using a repeater; the category_id is included in a hidden field. I want the user to be able to hover over a particular task and have a tooltip come up that provides the detail of that category from Recordset1 using the category_id in the hidden field. Edited July 7, 2013 by jcg31 Quote Link to comment https://forums.phpfreaks.com/topic/279938-unable-to-jump-error/#findComment-1439802 Share on other sites More sharing options...
mac_gyver Posted July 7, 2013 Share Posted July 7, 2013 if you are getting the data for the tool tip display using ajax, you would submit the category_id value and use it in a WHERE clause in the query. if you are producing all the tool tips and outputting the information all when the page is requested, you would use a JOIN query to get the relevant data you need from both tables at one time. Quote Link to comment https://forums.phpfreaks.com/topic/279938-unable-to-jump-error/#findComment-1439805 Share on other sites More sharing options...
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