n1concepts Posted July 12, 2013 Share Posted July 12, 2013 See table info - listing all records for 'users_id' column: ------------------ mysql> SELECT id,users_id, subscriptions_id,created from user_subscriptions; +-----+----------+------------------+---------------------+ | id | users_id | subscriptions_id | created | +-----+----------+------------------+---------------------+ | 108 | 170 | 5 | 2013-06-04 14:29:59 | | 109 | 171 | 5 | 2013-06-04 17:23:16 | | 110 | 177 | 5 | 2013-06-13 17:24:01 | | 111 | 177 | 5 | 2013-06-13 19:37:41 | | 112 | 178 | 5 | 2013-06-13 19:46:04 | | 113 | 178 | 1 | 2013-06-13 19:47:02 | | 114 | 178 | 5 | 2013-06-13 20:32:01 | | 115 | 178 | 5 | 2013-06-13 20:50:36 | | 116 | 180 | 5 | 2013-06-14 22:45:00 | | 117 | 181 | 5 | 2013-06-17 16:42:24 | | 118 | 183 | 5 | 2013-06-17 16:51:25 | | 120 | 184 | 5 | 2013-06-21 16:52:36 | | 121 | 184 | 5 | 2013-06-21 16:57:39 | | 122 | 169 | 5 | 2013-06-21 21:12:27 | | 123 | 169 | 5 | 2013-06-24 14:02:52 | | 124 | 169 | 5 | 2013-06-26 15:32:23 | | 125 | 185 | 5 | 2013-06-27 14:28:10 | | 126 | 186 | 5 | 2013-06-29 05:34:39 | | 127 | 187 | 5 | 2013-07-01 22:15:42 | | 128 | 169 | 5 | 2013-07-02 19:28:58 | | 129 | 169 | 5 | 2013-07-08 13:27:39 | | 130 | 169 | 5 | 2013-07-08 13:49:35 | | 131 | 169 | 5 | 2013-07-08 13:51:08 | | 132 | 169 | 5 | 2013-07-08 14:37:25 | | 133 | 169 | 5 | 2013-07-08 20:02:56 | | 134 | 169 | 1 | 2013-07-08 20:13:05 | | 135 | 169 | 2 | 2013-07-08 20:25:38 | | 136 | 190 | 5 | 2013-07-12 13:48:49 | | 137 | 191 | 5 | 2013-07-12 14:49:06 | +-----+----------+------------------+---------------------+ 29 rows in set Note: I'm trying to figure out the correct query that will list (only) the most recent entries - highlight in Bold above - which is a total of 14 entries (you can see there are 14 individaul 'users_id' values (shown below so to confirm the count that should be returned from the above query.) mysql> select DISTINCT(users_id) from user_subscriptions; +----------+ | users_id | +----------+ | 170 | | 171 | | 177 | | 178 | | 180 | | 181 | | 183 | | 184 | | 169 | | 185 | | 186 | | 187 | | 190 | | 191 | +----------+ 14 rows in set mysql> Objective: Define a MySQL select statement that will filter and only display the most recent record entry - for each 'users_id' column which will include subscriptions_id. I have been looking at using MAX() to filter and GROUPING on users_id but having issues w/that - reason I'm asking for help (LOL!) FYI: The below statement gets me the date info i need but that's where I'm concerned - what if there are multiple entries (although there should be if constraint on that column - i have to check). but what is there are two dates that are the same? This is my question and reason I'm thinking I need to filter/group on both - 'created' column and 'users_id'? mysql> SELECT MAX(created) max_date FROM user_subscriptions GROUP BY users_id; +---------------------+ | max_date | +---------------------+ | 2013-07-08 20:25:38 | | 2013-06-04 14:29:59 | | 2013-06-04 17:23:16 | | 2013-06-13 19:37:41 | | 2013-06-13 20:50:36 | | 2013-06-14 22:45:00 | | 2013-06-17 16:42:24 | | 2013-06-17 16:51:25 | | 2013-06-21 16:57:39 | | 2013-06-27 14:28:10 | | 2013-06-29 05:34:39 | | 2013-07-01 22:15:42 | | 2013-07-12 13:48:49 | | 2013-07-12 14:49:06 | +---------------------+ 14 rows in set I would appreciate some input to help me finish building this query to produce the unique rows based on most recent entry (per 'users_id'). Thx! Quote Link to comment Share on other sites More sharing options...
mac_gyver Posted July 12, 2013 Share Posted July 12, 2013 http://dev.mysql.com/doc/refman/5.6/en/example-maximum-column-group-row.html Quote Link to comment Share on other sites More sharing options...
Solution n1concepts Posted July 12, 2013 Author Solution Share Posted July 12, 2013 Never mind - I got it (Dah!) - thx mysql> SELECT users_id,id,subscriptions_id FROM user_subscriptions where created IN (SELECT MAX(created) max_date FROM user_subscriptions GROUP BY users_id) ORDER BY users_id DESC; +----------+-----+------------------+ | users_id | id | subscriptions_id | +----------+-----+------------------+ | 191 | 137 | 5 | | 190 | 136 | 5 | | 187 | 127 | 5 | | 186 | 126 | 5 | | 185 | 125 | 5 | | 184 | 121 | 5 | | 183 | 118 | 5 | | 181 | 117 | 5 | | 180 | 116 | 5 | | 178 | 115 | 5 | | 177 | 111 | 5 | | 171 | 109 | 5 | | 170 | 108 | 5 | | 169 | 135 | 2 | +----------+-----+------------------+ 14 rows in set Quote Link to comment Share on other sites More sharing options...
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