shinigaimi Posted July 18, 2013 Share Posted July 18, 2013 (edited) Hey all I am trying to filter if a variable doesnt exist in mysql to output something right now it does nothing any ideas? here is the code in question, I have tried !isset(), is_null(), empty() I am baffled! I know that array key #10/11 are not in mysql and they do not display anything I am trying to make it so if the $vehicle doesnt exist to do something the part where I am having issues is on line 32 the if statement Thanks! $array = array( "1" => "Flash", "2" => "Sunderer", "3" => "Lightning", "6" => "Prowler", "9" => "Mosquito", "10" => "Liberator", "11" => "Galaxy", "12" => "Harasser", ); foreach ($array as $key => $value) { $get = $dbh_beta->query("SELECT * FROM weapon_kills WHERE character_number=" . $char_id . " AND vehicle=" . $key. ""); $get->setFetchMode(PDO::FETCH_ASSOC); while ($display = $get->fetch()) { $vehicle = $display["vehicle"]; $value_nc = $display["value_nc"]; $value_tr = $display["value_tr"]; $value_vs = $display["value_vs"]; $total = $value_nc + $value_tr + $value_vs; ?> <?php if ($faction === "nc") { ?> <td><?php echo number_format($value_tr + $value_vs); ?></td> <td><?php echo number_format($value_tr); ?></td> <td><?php echo number_format($value_vs); ?></td> <?php } elseif ($faction === "tr") { ?> <td><?php echo number_format($value_nc + $value_vs); if(!$vehicle){ echo "-"; } ?> </td> <td><?php echo number_format($value_nc); ?></td> <td><?php echo number_format($value_vs); ?></td> <?php } elseif ($faction === "vs") { ?> <td><?php echo number_format($value_nc + $value_tr); ?></td> <td><?php echo number_format($value_nc); ?></td> <td><?php echo number_format($value_tr); ?></td> <?php } break; } } Edited July 18, 2013 by shinigaimi Quote Link to comment https://forums.phpfreaks.com/topic/280261-mysqlphp-error/ Share on other sites More sharing options...
mac_gyver Posted July 18, 2013 Share Posted July 18, 2013 if there is no row for a vehicle, there's nothing for your while(){} loop to loop over and the code inside your while loop doesn't even run. also, since there's no row, there are no values for $value_nc, $value_tr, and $value_vs and trying to access them would produce errors. what do you want the output to be in this case? a message, just zeros for those values,...? however, you should never run SELECT queries inside of loops. you should run ONE query that gets the rows you want. the following example code (untested) queries for the rows, then loops over the values in the $array and outputs whatever you want when there is no row or the data from the query if there is a row - $keys = implode(',',array_keys($array)); // get the keys as a list to query for $query = "SELECT * FROM weapon_kills WHERE character_number=$char_id AND vehicle IN($keys)"; $data = array(); foreach($dbh_beta->query($query,PDO::FETCH_ASSOC) as $row){ $data[$row['vehicle']] = $row; // store each row using the vehicle as the key/index } foreach ($array as $key => $value){ if(!isset($data[$key])){ // no vehicle, output whatever you want for that case... echo "<td colspan='3'>The vehicle $key:$value doesn't exist.</td>"; } else { // the vehicle exists in the table $row = $data[$key]; $value_nc = $row["value_nc"]; $value_tr = $row["value_tr"]; $value_vs = $row["value_vs"]; if($faction === "nc"){ echo "<td>".number_format($value_tr + $value_vs)."</td> <td>".number_format($value_tr)."</td> <td>".number_format($value_vs)."</td> "; } elseif ($faction === "tr"){ echo "<td>".number_format($value_nc + $value_vs)."</td> <td>".number_format($value_nc)."</td> <td>".number_format($value_vs)."</td> "; } elseif ($faction === "vs"){ echo "<td>".number_format($value_nc + $value_tr)."</td> <td>".number_format($value_nc)."</td> <td>".number_format($value_tr)."</td> "; } } } Quote Link to comment https://forums.phpfreaks.com/topic/280261-mysqlphp-error/#findComment-1441196 Share on other sites More sharing options...
Solution shinigaimi Posted July 21, 2013 Author Solution Share Posted July 21, 2013 I figured it out thanks! Quote Link to comment https://forums.phpfreaks.com/topic/280261-mysqlphp-error/#findComment-1441548 Share on other sites More sharing options...
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