Help capture part of a string please :)

[mds1256]

I have the following string (the parts between the double quotes is dynamic so not the same length or content each time) and I need to pick out who is logged on only, don't need any of the other content.

 

"explorer.exe","2012","Console","1","30,832 K","Running","MYDOMAIN\Administrator","0:00:02","N/A"

 

Now, I need to get the MYDOMAIN\Administrator part only (not including the quotes) and keep this in a variable.

 

Could someone help me out with this, i'm sure it is fairly easy for one of you regex experts to do.

 

 Thank you.

[.josh]

$user = array_slice(str_getcsv($string),6,1);

[ragax]

I am guilty of often failing to think of solutions like the one proposed by .josh, a neat solution which is a great example of when not to use regex.

For example, with a regex that aimed to retrieve the 7th string by counting commas, the "30,832" would really throw things off.

[mds1256]

 

$user = array_slice(str_getcsv($string),6,1);

Nice!

 

Thank you!