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not able to retrieve data...pls help...


Go to solution Solved by udaystrad,

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Got stuck with some coding..

the same sort of code is working somwhere else .....but not able to trace why this isnt workin?

 

 

Here's the code...

 

 
<?php
 
$host="localhost"; // Host name 
$username="root"; // Mysql username 
$password="india123"; // Mysql password 
$db_name="test"; // Database name
$members="members";
$mid=009;
$sa="Potekar";
 
$sql="sdadsaasd";
mysql_connect("$host", "$username", "$password")or die("cannot connect"); 
mysql_select_db("$db_name")or die("cannot select DB");
 
 
$then=mysql_query("SELECT * FROM $members WHERE MID='$mid' and Surname='$sa'");
$array = mysql_fetch_array($then);
$count=mysql_num_rows($array);
 
 
if (!$array) {
    echo "$sql<br>" . mysql_error();
}
 
else {
    // check if any records found
    if ($count==0) {
        echo "No matching records<br>";
    }
    else {
         
 $ra="sid";
        $sid=$array['FirstName'];
        echo $sid.'<br/>';    
    echo $ra;
 
}
}
 
 
?>
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  • phpMyAdmin 2.11.11.3 

NO errors

 

i think i m not able to retrieve data at selection of table....

i want it to retrieve data n display it out

 

there has to be somethin in the array i dont kno y its not showing n giving output ....

sdadsaasd

 

even if i manage to get smethin in array...

the count should cum 1.... which is 0 as it enters that loop and gives output....

 

no matching records

 

both of which are wrong.... is it syntax error .... or what i m not able to trace it out....?????

 

Edited by udaystrad

I recommend that you read the manual for mysql_query, mysql_num_rows and mysql_fetch_array and look carefully at what parameters they require and what they return.

 

edit: and turn error_reporting on.

Edited by Barand
  • Solution

k. i did find the mistake. i jus had to place the value in inverted comas ie

$mid='009';

as the value insterd in the table was text value.

 

Error reporting was already ON and like i said so there were no errors from the code.

 

thank you for the help.

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